使用 Apache HttpClient 和 Oauth 路标连接到 Twitter 流媒体 API 并使用带有空格的轨道？

Question

下面是一些尝试使用带有空格（“you will”）的曲目连接到 Twitter 的代码。它使用 Apache HttpClient 和 signpost oauth 或多或少类似于 tweetstream4j 确实如此。我使用

• signpost-core-1.2.1.1.jar
• signpost-commonshttp4-1.2.1.1.jar
• httpclient-4.0.1.jar
• httpcore-4.0.1.jar

如果我运行代码，我会从 Twitter 收到“401 未经授权”。如果使用不带空格的轨道（例如，“will”而不是“you will”），它可以正常连接并正常工作（只要我用有效值填写 oauth 消费者密钥和秘密、令牌和令牌秘密）。

有人发现问题所在吗？我认为这与 POST 正文中的 track 参数的 URL 编码有关，但我不确定。我一直在研究路标的工作原理，直到我的眼睛流血。

（这与 Java 中带有轨道的 Twitter 流 API 有关有空格吗？）。

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.List;
import java.util.logging.Logger;

import oauth.signpost.commonshttp.CommonsHttpOAuthConsumer;
import oauth.signpost.exception.OAuthCommunicationException;
import oauth.signpost.exception.OAuthExpectationFailedException;
import oauth.signpost.exception.OAuthMessageSignerException;

import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.client.methods.HttpRequestBase;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.message.BasicNameValuePair;
import org.apache.http.protocol.HTTP;

public class TwitterSpaceTest {
private static Logger logger = Logger.getLogger(
    TwitterSpaceTest.class.getName());

private static final String API_PROTOCOL = "http";
private static final String API_DOMAIN = "stream.twitter.com";
private static final String API_URL = "1/";
private static final String FILTER_URL = API_URL + "statuses/filter.json";

public static void readFrom(HttpRequestBase requestMethod) throws IOException {
    DefaultHttpClient client = new DefaultHttpClient();
    HttpResponse response = client.execute(requestMethod);
    HttpEntity entity = response.getEntity();
    if (entity == null) throw new IOException("No entity");
    BufferedReader br = new BufferedReader(new InputStreamReader(
        entity.getContent(), "UTF-8"));
    while (true) {
       String line = br.readLine();
       if (line != null && !line.isEmpty()) {
       System.out.println(line);
       }
    }
}

public static HttpRequestBase getConnection()
    throws OAuthMessageSignerException,
    OAuthExpectationFailedException, OAuthCommunicationException,
    IllegalStateException, IOException {
    String base = FILTER_URL;
    List<NameValuePair> params = new ArrayList<NameValuePair>();
    // No spaces
//        params.add(new BasicNameValuePair("track", "will"));
    // Spaces
    params.add(new BasicNameValuePair("track", "you will"));

    HttpPost method = new HttpPost(API_PROTOCOL + "://" + API_DOMAIN + "/"
        + base);
    logger.info("" + method.getURI());

    UrlEncodedFormEntity postEntity = new UrlEncodedFormEntity(params,
        HTTP.UTF_8);
    method.setEntity(postEntity);

    String consumerKey = "...";
    String consumerSecret = "..."
    CommonsHttpOAuthConsumer consumer = new CommonsHttpOAuthConsumer(
        consumerKey, consumerSecret);
    String token = "...";
    String tokenSecret = "...";
    consumer.setTokenWithSecret(token, tokenSecret);
    consumer.sign(method);

    return method;
}

public static void main(String[] args) throws Exception {
    readFrom(getConnection());
}
}

Answer 1

您应该将 api 链接中的 http 更改为 https