preg_replace 删除标点符号、空格和单词所有格形式？

Question

$text =
"<tab><return><nbsp>O'Neil  really  
likes his pudding's, he really really does!!!1.5"

如果可能的话，我希望有这个，其中 '' 是一个实际的制表符 \t 空间，而不是字面上的 '' >

$text = "O'Neil really likes his pudding he really really does 1.5"

删除白色步伐并用一个空格、标点符号替换它们，保留撇号后面的数字或任何不是 's' 的内容。

非常感谢！

Answer 1

$string = trim(preg_replace(array('~[:;!?]|[.,](?![0-9])|\'s~', '~\s+~'), array('', ' '), $string));

首先去掉 的，然后用一个空格替换多个空格。最终它会删除前导和尾随空白。