序列化指向没有默认构造函数的类的指针时，无法覆盖 save_construct_data

发布于 2024-09-30 17:18:34 字数 1295 浏览 10 评论 0原文

我正在尝试遵循这个示例 http:// /www.boost.org/doc/libs/1_42_0/libs/serialization/doc/serialization.html#constructors 但我不断收到错误。按照这个例子，我在尝试访问私有变量时遇到错误（这很公平）：

bs.cpp:10: error: ‘const int my_class::m_attribute’ is private

但是，如果我将 save_construct_data 添加为友元，则会出现歧义错误：

/usr/include/boost/serialization/serialization.hpp:148: error: call of overloaded ‘save_construct_data(boost::archive::text_oarchive&, const my_class*&, const boost::serialization::version_type&)’ is ambiguous
/usr/include/boost/serialization/serialization.hpp:83: note: candidates are: void boost::serialization::save_construct_data(Archive&, const T*, unsigned int) [with Archive = boost::archive::text_oarchive, T = my_class]
bs.cpp:10: note:                 void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]
bs.cpp:29: note:                 void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]

我可以将函数定义移动到友元声明中，但这很丑陋。

接下来我应该尝试什么？

谢谢，杰恩

原文

I'm trying to follow this example http://www.boost.org/doc/libs/1_42_0/libs/serialization/doc/serialization.html#constructors but I keep getting errors. Following the example, I get an error trying to access a private variable (fair enough):

bs.cpp:10: error: ‘const int my_class::m_attribute’ is private

But, if I add save_construct_data as a friend, I get an ambiguity error:

/usr/include/boost/serialization/serialization.hpp:148: error: call of overloaded ‘save_construct_data(boost::archive::text_oarchive&, const my_class*&, const boost::serialization::version_type&)’ is ambiguous
/usr/include/boost/serialization/serialization.hpp:83: note: candidates are: void boost::serialization::save_construct_data(Archive&, const T*, unsigned int) [with Archive = boost::archive::text_oarchive, T = my_class]
bs.cpp:10: note:                 void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]
bs.cpp:29: note:                 void boost::serialization::save_construct_data(Archive&, const my_class*, unsigned int) [with Archive = boost::archive::text_oarchive]

I can move the function definition to the friend declaration, but that's just ugly.

What should I try next?

Thanks,
Jayen

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像你 2024-10-07 17:18:34

save_construct_data 必须先声明，然后才能添加好友。关于处于不同命名空间中的事情。像这样：

namespace boost { namespace serialization {
template<class Archive>
inline void save_construct_data(Archive & ar, const my_class * t, const unsigned int file_version);
}}

但是，因为这取决于 my_class，所以你也必须声明 my_class：

class my_class;

所以整个事情看起来像 http://pastebin.com/embed_iframe.php?i=aFyCpjyY

save_construct_data has to be declared before it can be friended. Something about being in a different namespace. Like this:

namespace boost { namespace serialization {
template<class Archive>
inline void save_construct_data(Archive & ar, const my_class * t, const unsigned int file_version);
}}

But, because that depends on my_class, you have to declare my_class as well: