如何测试一个矩形是否在另一个矩形中？
好吧，我正在开发一款游戏，我发现我的敌人不喜欢我的碰撞检测，而我的碰撞检测对我的玩家来说非常有效。经过一番调试后，我发现这是因为我的敌人比我的方块大，而我的玩家比我的方块小。
现在我需要能够结交大敌人和老板，所以这是行不通的。所以我需要找到一种更好的方法来测试碰撞检测。这就是我目前正在做的：
向上和向下：
if((enemy.left > tile.left && enemy.left < tile.right || enemy.right > tile.left && enemy.right < tile.right) && enemy.top < tile.bottom && enemy.bottom > tile.top){
//collision
}
向左和向右：
if((enemy.top > tile.top && enemy.top < tile.bottom || enemy.bottom > tile.top && enemy.bottom < tile.bottom) && enemy.left < tile.right && enemy.right > tile.left){
//colision
}
Alright, so I'm working on a game and I have found out that my enemies don't like my collision detection that works perfectly for my player. After a little debugging I found out it's because my enemies are bigger than my tiles, while my player is smaller than my tiles.
Now I need to be able to make big enemies and bosses, so this just won't do. so I need to figure out a better way to test collision detection. This is how I am currently doing it:
up and down:
if((enemy.left > tile.left && enemy.left < tile.right || enemy.right > tile.left && enemy.right < tile.right) && enemy.top < tile.bottom && enemy.bottom > tile.top){
//collision
}
left and right:
if((enemy.top > tile.top && enemy.top < tile.bottom || enemy.bottom > tile.top && enemy.bottom < tile.bottom) && enemy.left < tile.right && enemy.right > tile.left){
//colision
}
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在 Java 中，使用
相交（矩形 r）。In Java, use
intersects(Rectangle r).以下是如何正确进行分离轴测试（对于定向边界框，就像您所做的那样）。
访问此站点，并使用图 3，一次将所有这些都变成真实的。然后一次一个地打破每一项测试。您将根据经验看到它的工作原理，并且非常简单：
http: //www.metanetsoftware.com/technique/tutorialA.html#section1
如果您愿意，请通读整套教程。一旦您开始在游戏中加入更多功能，一切都是值得的:)
Here's how to correctly do the separating axis tests (for oriented bounding boxes, like you're doing).
Go to this site, and play with Figure 3, making all of these true one at a time. Then break each of the tests, one at a time. You'll see empirically that it works, and is about as simple as you can get:
http://www.metanetsoftware.com/technique/tutorialA.html#section1
If you feel like it, read through the whole set of tutorials. It'll be worth it once you start packing more features into your game :)
在 .NET 语言中，您可以使用 Rectangle.IntersectsWith(Rectangle other) 方法来执行非常基本的碰撞检测。
In .NET languages, you can use the
Rectangle.IntersectsWith(Rectangle other)method to perform very basic collision detection.对于任何使用 Objective-C 寻找相同答案的人，您可以使用：
For anyone working in Objective-C looking for the same answer you can use:
我认为问题在于
（在第一个代码中），只有当敌人完全位于图块内（高度方向）时，这才会成立，
就像您对左+右检查所做的那样。
只是为了澄清这一点意味着您给出的第一个检查将是：
}
并且我认为您不需要单独的上/下左/右检查，如果敌人的任何部分在图块内，这应该返回 true
I think the problem lies in
(In first code), this will only be true if enemy is within the tile fully (height-wise)
Like you have done with the left + right check.
Just to clarify this would mean the first check you gave would be:
}
And with this I dont think you would need seperate up/down left/right checks, this should return true if ANY part of enemy is within tile
精灵比图块更宽，但“左右”代码不会检查这种情况。
如果我绘制你的代码，它只是检查敌人左侧或敌人右侧是否位于该图块内：
但如果整个图块位于敌人区域内，则不会检测到命中：
同样，图块较小垂直于敌人，因此有必要检查整个瓷砖是否位于敌人内部。
完整的图/伪代码是：
The sprite is wider than the tile, but the "left-right" code doesn't check for that case.
If i graph your code, it simply checks whether the enemy left or the enemy right lies within the tile:
but if the entire tile lies within the enemy region, no hit is detected:
Similarly, the Tile is smaller vertially than the enemy, so it is necessary to check the if the entire tile lies within the enemy.
The complete graph/pseudo code is:
在
.Net中，Rect类中已经有一个名为Intersect(Rect rect)的方法。In
.Netthere is already a method namedIntersect(Rect rect)inRectclass.