将 gevent 与 python xmlrpclib 结合使用

发布于 2024-09-29 20:22:15 字数 698 浏览 2 评论 0原文

是否可以将 python 的标准库 xmlrpclib 与 gevent 一起使用?目前我尝试使用monkey.patch_all(),但没有成功。

from gevent import monkey
monkey.patch_all()

import gevent

import time

import xmlrpclib
from SimpleXMLRPCServer import SimpleXMLRPCServer

import urllib2

def fetch(url):
        g = gevent.spawn(urllib2.urlopen, url)
        return g.get().read()
def is_even(n):
    return n%2 == 0

def req(url):
        return fetch(url)

server = SimpleXMLRPCServer(("localhost", 8000))
print "Listening on port 8000..."
server.register_function(is_even, "is_even")
server.register_function(req, "req")
server.serve_forever()

urllib2.urlopen 正在阻止服务器。在我看来,monkey.patch_all 没有修补套接字,这就是它阻塞的原因。

Is it possible to use python's standard libs xmlrpclib with gevent? Currently i'm tried to use monkey.patch_all(), but without success.

from gevent import monkey
monkey.patch_all()

import gevent

import time

import xmlrpclib
from SimpleXMLRPCServer import SimpleXMLRPCServer

import urllib2

def fetch(url):
        g = gevent.spawn(urllib2.urlopen, url)
        return g.get().read()
def is_even(n):
    return n%2 == 0

def req(url):
        return fetch(url)

server = SimpleXMLRPCServer(("localhost", 8000))
print "Listening on port 8000..."
server.register_function(is_even, "is_even")
server.register_function(req, "req")
server.serve_forever()

urllib2.urlopen is blocking server. It looks to me, that monkey.patch_all did not patched socket, that's why it blocks.

如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。

扫码二维码加入Web技术交流群

发布评论

需要 登录 才能够评论, 你可以免费 注册 一个本站的账号。

评论(1

來不及說愛妳 2024-10-06 20:22:15

套接字已修补得很好,但您的代码还存在其他问题。

首先,这

def fetch(url):
    g = gevent.spawn(urllib2.urlopen, url)
    return g.get().read()

一样

def fetch(url):
    return urllib2.urlopen(url).read()

与您在这里生成一个新的 greenlet 但然后阻止当前的 greenlet 直到新的 greenlet 完成 。它不会使事情并发。这与运行 urlopen 并等待其完成完全相同。

其次,为了利用 gevent,必须有多个轻量级线程 (greenlet) 同时运行。

然而,SimpleXMLRPCServer 的定义意味着

class SimpleXMLRPCServer(SocketServer.TCPServer,
                         SimpleXMLRPCDispatcher):

它一次为一个连接提供服务。

如果您创建自己的 SimpleXMLRPCServer 类,但使用 ThreadingTCPServer 而不是 TCPServer,那么您应该能够从此处使用 gevent 中受益。

monkey.patch_all() 修补线程,使其成为基于 greenlet 的,因此此类服务器将为每个新连接生成一个新的 greenlet。

The socket is patched fine, but there are other problems with your code.

First, this

def fetch(url):
    g = gevent.spawn(urllib2.urlopen, url)
    return g.get().read()

is the same as

def fetch(url):
    return urllib2.urlopen(url).read()

You're spawning a new greenlet here but then blocking the current one until that new one is done. It does not make things concurrent. It's exactly the same as just running urlopen and waiting for it to finish.

Second, in order to take advantage of gevent there got to be more than one lightweight thread (greenlet) running at the same time.

SimpleXMLRPCServer, however, is defined as

class SimpleXMLRPCServer(SocketServer.TCPServer,
                         SimpleXMLRPCDispatcher):

which means it serves one connection at a time.

If you make your own SimpleXMLRPCServer class, but use ThreadingTCPServer instead of TCPServer, you should be able to benefit from using gevent here.

monkey.patch_all() patches threading to become greenlet-based, so such server will spawn a new greenlet for each new connection.

~没有更多了~
我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
原文