在 SQL UNION 查询中添加列内容

发布于 2024-09-29 19:21:04 字数 587 浏览 0 评论 0原文

到目前为止,我有这个查询,

SELECT
    COUNT(f.code_id) as item_count, 
    f.code_desc
FROM 
    foo f
    INNER JOIN foohistory fh ON f.history_id = fh.history_id
WHERE
    MONTH(fh.create_dt) = 6
    AND YEAR(fh.create_dr) = 2010
GROUP BY 
    f.code_desc

    UNION ALL

SELECT
    COUNT(b.code_id) as item_count, 
    b.code_desc
FROM 
    bar b
    INNER JOIN barhistory bh ON b.history_id = bh.history_id
WHERE
    MONTH(bh.create_dt) = 6
    AND YEAR(bh.create_dr) = 2010
GROUP BY 
    b.code_desc

我的目标是联合这两个查询,为每个 code_desc 添加 SUM 'item_count' 列。这可能吗?

So far I have this query

SELECT
    COUNT(f.code_id) as item_count, 
    f.code_desc
FROM 
    foo f
    INNER JOIN foohistory fh ON f.history_id = fh.history_id
WHERE
    MONTH(fh.create_dt) = 6
    AND YEAR(fh.create_dr) = 2010
GROUP BY 
    f.code_desc

    UNION ALL

SELECT
    COUNT(b.code_id) as item_count, 
    b.code_desc
FROM 
    bar b
    INNER JOIN barhistory bh ON b.history_id = bh.history_id
WHERE
    MONTH(bh.create_dt) = 6
    AND YEAR(bh.create_dr) = 2010
GROUP BY 
    b.code_desc

My goal is to UNION these two queries add SUM the 'item_count' columns foreach code_desc. Is this possible?

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评论(2

冰魂雪魄 2024-10-06 19:21:04

如果没有有关代码的更多信息,例如两个表之间的代码是否可能互斥,请使用:

SELECT x.code_desc,
       SUM(x.item_count)
 FROM (SELECT f.code_desc,
              COUNT(f.code_id) as item_count
         FROM foo f
         JOIN foohistory fh ON f.history_id = fh.history_id
        WHERE MONTH(fh.create_dt) = 6
          AND YEAR(fh.create_dr) = 2010
     GROUP BY f.code_desc
       UNION ALL
       SELECT b.code_desc,
              COUNT(b.code_id) as item_count    
         FROM bar b
         JOIN barhistory bh ON b.history_id = bh.history_id
        WHERE MONTH(bh.create_dt) = 6
          AND YEAR(bh.create_dr) = 2010
     GROUP BY b.code_desc) x
GROUP BY x.code_desc

Without more information about the codes, like if it's possible that codes are mutually exclusive between the two tables, use:

SELECT x.code_desc,
       SUM(x.item_count)
 FROM (SELECT f.code_desc,
              COUNT(f.code_id) as item_count
         FROM foo f
         JOIN foohistory fh ON f.history_id = fh.history_id
        WHERE MONTH(fh.create_dt) = 6
          AND YEAR(fh.create_dr) = 2010
     GROUP BY f.code_desc
       UNION ALL
       SELECT b.code_desc,
              COUNT(b.code_id) as item_count    
         FROM bar b
         JOIN barhistory bh ON b.history_id = bh.history_id
        WHERE MONTH(bh.create_dt) = 6
          AND YEAR(bh.create_dr) = 2010
     GROUP BY b.code_desc) x
GROUP BY x.code_desc
清晰传感 2024-10-06 19:21:04

是的,做这样的事情

SELECT Sum(unionedTable.item_count)
FROM 
(
//your query 


) as unionedTable

Yeah, doing something like this

SELECT Sum(unionedTable.item_count)
FROM 
(
//your query 


) as unionedTable
~没有更多了~
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