Python：csvwriter 的问题

Question

我正在尝试将数据（主要是日期、布尔值和浮点数据类型）写入 CSV 文件格式。这是我的代码片段：

# Write data to file
with open(OUTPUT_DIR + output_filename,'w') as outputfile:
    wrtr = csv.writer(outputfile, delimiter=',', quotechar='"')

    for x, y in datarows.items():
        a,b,c,d,e,f,g = (somedate.strft('%Y-%m-%d'),0,6058.7,False,1913736200,0,False)                     
        rowstr = "{0},{1},{2},{3},{4},{5},{6}".format(a,b,c,d,e,f,g)
        wrtr.writerow(rowstr)

    outputfile.close()

文件内容如下所示：

2,0,0,7,-,10,-,03,",",0,",",6,0,5,8,.,7,",",F,a,l ,s,e,",",1,9,1,3,7,3,6,2,0,0,",",0,",",F,a,l,s,e

我目前正在使用原始文件对象写入文件 - 但我更喜欢使用 csvwrite - 因为这就是它的用途

Answer 1

尝试使用 wrtr.writerow([a,b,c,d,e,f,g]) 来代替。

writerow() 参数必须是值列表，而不是文本行。 csv.writer 的想法是，它将根据 CSV 规则格式化行值。

您得到的结果是由于 writerow() 将您的 rowstr 字符串解释为字符列表。

Answer 2

看看这个例子也许它可以帮助你：

import datetime

with open('file.csv','w') as outputfile:
    wrtr = csv.writer(outputfile, delimiter=',', quotechar='"')
    a = (datetime.datetime.now().strftime('%Y-%m-%d'),0,6058.7,False,1913736200,0,False)
    wrtr.writerow(a)  # pass an iterable here

    # outputfile.close() you don't have to call close() because you use with

file.csv

2010-11-01,0,6058.7,False,1913736200,0,False

希望这可以帮助你