在IB中创建的NSWindow不会在应用程序中以模态方式显示

发布于 2024-09-29 14:58:39 字数 1521 浏览 6 评论 0原文

我有一个应用程序，当按下按钮时它应该显示一个模式窗口。我对此有一些疑问，但我会将其范围缩小到令我头疼的问题。

我想补充一点，我已经在做类似的事情，但应用于这种特殊情况时是行不通的。我已经做的是以模态方式显示 NSOpenPanel。这是它的代码。

此代码位于 appDelegate 内部。

-(IBAction) respondToPublishAction:(id) sender {
    NSArray *fileTypes = [NSArray arrayWithObjects:@"xml", @"txt", nil];

    NSOpenPanel *oPanel = [NSOpenPanel openPanel];

    NSString *startingDir = [[NSUserDefaults standardUserDefaults] objectForKey:@"StartingDirectory"];

    if (!startingDir)
        startingDir = NSHomeDirectory();

//Setting the attributes
[oPanel setAllowsMultipleSelection:NO];
[oPanel setTitle:@"XML file for publishing services"];
[oPanel beginSheetForDirectory:startingDir file:nil types:fileTypes
                modalForWindow:[self window] modalDelegate:self
                didEndSelector:@selector(openPanelDidEnd:returnCode:contextInfo:)
                   contextInfo:nil];
}

现在我想做的事情是行不通的，

我创建了一个 xib 文件，它有一个 HUD 窗口（它在 IB 中的命名方式），其作用类似于 NSPanel。我创建了一个监听按钮（testButton）的 windowcoroller。代码如下：

@interface BrowserWindowController : NSWindowController {
}
-(IBAction) testButton:(id) sender;
@end

我将 xib 文件的文件所有者设置为 BrowserWindowController 类，并将按钮与测试按钮链接起来。

回到 appDelegate 当单击按钮时我想以模式方式显示此面板。代码如下：

- (IBAction) respondToBrowseAction:(id) sender {
browsePanel = [[BrowserWindowController alloc] initWithWindowNibName:@"BroserWindow"];
}

我在 API 中没有看到任何像 NSOpenPanel 这样以模态方式显示此窗口的函数。

感谢任何可能回答的人。

原文

I have an application that when pressing a button it should show a modal window. I have some questions about it but I'm going to narrow it to what it's giving me a headache.

I want to add that I'm already doing something alike that when applied to this particularly case won't work. What I already do is to show modally a NSOpenPanel. This is the code for it.

This code is inside the appDelegate.

-(IBAction) respondToPublishAction:(id) sender {
    NSArray *fileTypes = [NSArray arrayWithObjects:@"xml", @"txt", nil];

    NSOpenPanel *oPanel = [NSOpenPanel openPanel];

    NSString *startingDir = [[NSUserDefaults standardUserDefaults] objectForKey:@"StartingDirectory"];

    if (!startingDir)
        startingDir = NSHomeDirectory();

//Setting the attributes
[oPanel setAllowsMultipleSelection:NO];
[oPanel setTitle:@"XML file for publishing services"];
[oPanel beginSheetForDirectory:startingDir file:nil types:fileTypes
                modalForWindow:[self window] modalDelegate:self
                didEndSelector:@selector(openPanelDidEnd:returnCode:contextInfo:)
                   contextInfo:nil];
}

Now What I'm trying to do and that won't work

I created a xib file that has a HUD Window (how it's named in IB) that acts like a NSPanel. I created a windowcotroller that listen to a button (testButton). Here's the code:

@interface BrowserWindowController : NSWindowController {
}
-(IBAction) testButton:(id) sender;
@end

I set the file's owner of the xib file to be of the class BrowserWindowController and linked the button with the testbutton.

Back to the appDelegate when a button is clicked I want to show this Panel modally. Here's the code:

- (IBAction) respondToBrowseAction:(id) sender {
browsePanel = [[BrowserWindowController alloc] initWithWindowNibName:@"BroserWindow"];
}

I don't see any function in the API like NSOpenPanel to show this window modally.

Thx to anyone who might answer.

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情未る 2024-10-06 14:58:39

没有用于模态运行的 NSWindow API 的原因是应用程序要进入模态模式。请参阅模态窗口工作原理和< a href="http://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/Sheets/Sheets.html" rel="nofollow">表格简介。

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