将 nsarray 合并到 nsset 并避免 iPhone 上 Objective-C 中的重复

Question

编辑：更好的例子...

所以我有一个“现有”对象的 NSMutableSet，我想下载 JSON 数据，解析它，并将这些新对象与我现有的对象合并，更新任何重复项与新下载的。现有对象集如下所示：

NSArray *savedObjects = [NSArray arrayWithObjects:
    [NSDictionary dictionaryWithObjectsAndKeys:@"1", @"id", @"hello there", @"body", @"200", @"score", nil],
    [NSDictionary dictionaryWithObjectsAndKeys:@"2", @"id", @"hey now", @"body", @"10", @"score", nil],
    [NSDictionary dictionaryWithObjectsAndKeys:@"3", @"id", @"welcome!", @"body", @"123", @"score", nil],
    nil
];
self.objects = [NSMutableSet setWithArray:savedObjects];

// after downloading and parsing JSON... I have an example array of objects like this:

NSArray *newObjects = [NSArray arrayWithObjects:
    [NSDictionary dictionaryWithObjectsAndKeys:@"1", @"id", @"hello there", @"body", @"9999", @"score", nil],
    [NSDictionary dictionaryWithObjectsAndKeys:@"4", @"id", @"what's new", @"body", @"22", @"score", nil],
    nil
];

例如，合并此新对象后，id 为 1 的对象现在的得分为 9999，并且 id 为 4 的新对象将添加到该集合中。

我真的想避免为每个新对象循环遍历 NSMutableSet 只是为了检查 @"id" 属性是否存在...我想我可以使用 addObjectsFromArray 来合并这些新对象，但它看起来像因为属性不同（例如：得分：9999）它没有将新对象视为集合中的现有对象。

我使用数字作为字符串来简化这个示例。我还想避免使用仅限 iOS SDK 4.0 的功能，因为该应用程序将兼容 3.0。

非常感谢！我很感激！

Answer 1

从你的问题中不能完全确定（因为它是一个 iphone 问题，应该使用客观的 c 表示法），但听起来 NSDictionary 可能是你最好的朋友。

Answer 2

最好的选择是使用 @"id" 参数将第一组转换为字典。下面是一些应该执行您想要的操作的代码，它甚至可以处理没有 @"id" 参数的字典的情况（此时它们不会被合并，只是包含在结果中）：

// here is the NSSet you already have
self.objects = [NSSet setWithObjects:
    [NSDictionary dictionaryWithObjectsAndKeys:@"1", @"id", @"hello there", @"body", @"200", @"score", nil],
    [NSDictionary dictionaryWithObjectsAndKeys:@"2", @"id", @"hey now", @"body", @"10", @"score", nil],
    [NSDictionary dictionaryWithObjectsAndKeys:@"3", @"id", @"welcome!", @"body", @"123", @"score", nil],
    nil];

// after downloading and parsing JSON... I have an example array of objects like this:

NSArray *newObjects = [NSArray arrayWithObjects:
    [NSDictionary dictionaryWithObjectsAndKeys:@"1", @"id", @"hello there", @"body", @"9999", @"score", nil],
    [NSDictionary dictionaryWithObjectsAndKeys:@"4", @"id", @"what's new", @"body", @"22", @"score", nil],
    nil];

// Convert self.objects into a dictionary for merging purposes
NSMutableDictionary *dict = [NSMutableDictionary dictionaryWithCapacity:[self.objects count]];
NSMutableSet *remainder = [NSMutableSet set]; // for objects with no @"id"
for (NSDictionary *obj in self.objects) {
    NSString *objId = [obj objectForKey:@"id"];
    if (objId) {
        [dict setObject:obj forKey:objId];
    } else {
        [remainder addObject:obj];
    }
}

// merge the new objects in
for (NSDictionary *obj in newObjects) {
    NSString *objId = [obj objectForKey:@"id"];
    if (objId) {
        // merge the new dict with the old
        // if you don't want to merge the dict and just replace,
        // simply comment out the next few lines
        NSDictionary *oldObj = [dict objectForKey:objId];
        if (oldObj) {
            NSMutableDictionary *newObj = [NSMutableDictionary dictionaryWithDictionary:oldObj];
            [newObj addEntriesFromDictionary:obj];
            obj = newObj;
        }
        // stop commenting here if you don't want the merging
        [dict setObject:newObj forKey:objId];
    } else {
        [remainder addObject:obj];
    }
}

// add the merged dicts back to the set
[remainder addObjectsFromArray:[dict allValues]];
self.objects = remainder;

Answer 3

NSArray *array = ... // contains the new dictionary objects.
NSMutableSet *set = ... // contains the existing set of dictionary objects. 

for (id arrayItem in array)
{
    id setItem = [[set filteredSetUsingPredicate:[NSPredicate predicateWithFormat:@"id.intValue = %d", [[arrayItem valueForKey:@"id"] intValue]]] anyObject];
    if (setItem != nil)
    {
        [set removeObject:setItem];
        [set addObject:arrayItem];
    }
}