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如何使用 VBScript 列出具有方法的所有 WMI 类？

发布于 2024-09-29 01:17:34 字数 37 浏览 2 评论 0原文

使用 VBScript，如何列出所有具有方法的 WMI 类？

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青瓷清茶倾城歌 2024-10-06 01:17:34

运行 SELECT 架构查询以获取命名空间中所有类的列表，然后检查每个类的 Methods_.Count：

strComputer  = "."
strNamespace = "root\cimv2"

Set oWMI = GetObject("winmgmts:\\" & strComputer & "\" & strNamespace)
Set colClasses = oWMI.ExecQuery("SELECT * FROM meta_class") 

For Each oClass in colClasses
  If oClass.Methods_.Count > 0 Then
    WScript.Echo oClass.Path_.Class
  End If
Next

您可能希望将结果限制为动态并且仅静态类，就像 WMI Code Creator 所做的那样。为此，请为相应的类限定符添加额外的检查。

...
For Each oClass in colClasses

  For Each oQualifier In oClass.Qualifiers_
    strQualName = LCase(oQualifier.Name)

    If strQualName = "dynamic" OR strQualName = "static" Then
      If oClass.Methods_.Count > 0 Then
        WScript.Echo oClass.Path_.Class
      End If
    End If

  Next
Next

我还建议您阅读WMI 脚本入门：第 2 部分一文。它通过示例详细解释了 WMI 概念和基础结构，并且可能已经包含了您未来问题的答案。 :)

Run a SELECT schema query to get a list of all classes in a namespace, and then check each class's Methods_.Count:

strComputer  = "."
strNamespace = "root\cimv2"

Set oWMI = GetObject("winmgmts:\\" & strComputer & "\" & strNamespace)
Set colClasses = oWMI.ExecQuery("SELECT * FROM meta_class") 

For Each oClass in colClasses
  If oClass.Methods_.Count > 0 Then
    WScript.Echo oClass.Path_.Class
  End If
Next

You may want to limit the results to dynamic and static classes only, like WMI Code Creator does. To do this, add an additional check for the corresponding class qualifiers.

...
For Each oClass in colClasses

  For Each oQualifier In oClass.Qualifiers_
    strQualName = LCase(oQualifier.Name)

    If strQualName = "dynamic" OR strQualName = "static" Then
      If oClass.Methods_.Count > 0 Then
        WScript.Echo oClass.Path_.Class
      End If
    End If

  Next
Next

I also suggest that you read the WMI Scripting Primer: Part 2 article. It explains the WMI concepts and infrastructure in detail and with examples, and may already hold answers to your future questions. :)

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