CS0019 运算符不能应用于“bool”类型的操作数;和“int”
该程序响应以下任务:
“创建一个名为 Sum()
的方法,该方法接受任意数量的整数参数,并且 显示它们的总和。编写一个 Main()
方法,该方法演示 Sum()
方法在传递 1、3、5 或 10 个整数的数组时可以正常工作。将程序另存为 UsingSum.cs
。”,
来自 Microsoft® Visual C#® 2008,面向对象编程简介,3e,Joyce Farrell
我的代码位于“//第 1 步:“部分出现 CS0019 错误,该错误表明它不能应用于 bool
和 int
类型的操作数。
我高度怀疑这还存在其他问题代码,但这比我四个小时前的代码有了很大的进步......
using System;
public class UsingSum
{
public static void Main()
{
Sum();
}
public static void Sum()
{
// Step 1: Addition of one, three, five
bool q, r, s;
int firstTotal, n, o, p;
string k, l, m;
Console.Write("Type the number 1: ");
k = Console.ReadLine();
n = Convert.ToInt32(k);
q = Convert.ToBoolean(k);
Console.WriteLine();
if (q == 1)
Console.WriteLine("Input accepted.");
else if (!(q == 1))
{
Console.WriteLine("Error: You didn't type the number 1. Please try again.");
Console.Write("Type the number 1: ");
k = Console.ReadLine();
n = Convert.ToInt32(k);
q = Convert.ToBoolean(k);
}
}
Console.Write("Type the number 3: ");
l = Console.ReadLine();
r = Convert.ToBoolean(l);
o = Convert.ToInt32(l);
Console.WriteLine();
if (r <= 2 || r >= 4)
{
Console.WriteLine("Error: You didn't type the number 3. Please try again.");
Console.Write("Type the number 3: ");
l = Console.ReadLine();
r = Convert.ToBoolean(l);
o = Convert.ToInt32(l);
}
else
if (r = 3)
Console.WriteLine("Input accepted.");
Console.Write("Type the number 5: ");
m = Console.ReadLine();
p = Convert.ToInt32(m);
s = Convert.ToBoolean(m);
Console.WriteLine();
if (s <= 4 || s >= 6)
{
Console.WriteLine("Error: You didn't type the number 5. Please try again.");
Console.Write("Type the number 5: ");
m = Console.ReadLine();
p = Convert.ToInt32(m);
s = Convert.ToBoolean(m);
}
else
if (s = 5)
Console.WriteLine("Input accepted.");
firstTotal = n + o + p;
Console.WriteLine("{0} + {1} + {2} = {3}", n, o, p, firstTotal);
// Step 2: Entering integers for array[10]
int a, arrayTotal, b, c, d, e, f, g, h, i, j, unlimited;
Console.Write("Enter first integer for addition: ");
a = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter second integer for addition: ");
b = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter third integer for addition: ");
c = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter forth integer for addition: ");
d = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter fifth integer for addition: ");
e = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter sixth integer for addition: ");
f = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter seventh integer for addition: ");
g = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter eighth integer for addition: ");
h = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter ninth integer for addition: ");
i = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter tenth integer for addition: ");
j = Convert.ToInt32(Console.ReadLine());
arrayTotal = a + b + c + d + e + f + g + h + i +j;
Console.WriteLine("The total of {0} + {1} + {2} + {3} + {4} + {5} + {6} + {7} + {8} + {9} = {10}",
a, b, c, d, e, f, g, h, i, j, arrayTotal);
// Step 3: Unlimited array addition
int[] arrayTwo;
int total, y;
string ADD, x;
while(Console.Write("Enter an integer for addition, or type ADD to calculate the sum: "))
{
x = Console.ReadLine();
y = Convert.ToInt32(x);
if (x == ADD)
Console.WriteLine("Calculating the total sum");
}
for (y = 0; y < arrayTwo.Length; ++y)
{
total = arrayTwo[y] + arrayTwo[y];
++arrayTwo[y];
Console.WriteLine("========================");
Console.WriteLine("=/n= The total is: {0} =/n=", total);
Console.WriteLine("========================");
}
}
}
This program is in response to the assignment:
"Create a method named Sum()
that accepts any number of integer parameters and
displays their sum. Write a Main()
method that demonstrates that the Sum()
method works correctly when passed one, three, five, or an array of ten integers. Save the program as UsingSum.cs
."
from Microsoft® Visual C#® 2008, An Introduction to Object-Oriented Programming, 3e, Joyce Farrell
My code in the "//step 1:" part is getting the CS0019 error, which states that it cannot be applied to operands of type bool
and int
.
I highly suspect there are also other problems with this code, but it's a great improvement over what I had four hours ago…
using System;
public class UsingSum
{
public static void Main()
{
Sum();
}
public static void Sum()
{
// Step 1: Addition of one, three, five
bool q, r, s;
int firstTotal, n, o, p;
string k, l, m;
Console.Write("Type the number 1: ");
k = Console.ReadLine();
n = Convert.ToInt32(k);
q = Convert.ToBoolean(k);
Console.WriteLine();
if (q == 1)
Console.WriteLine("Input accepted.");
else if (!(q == 1))
{
Console.WriteLine("Error: You didn't type the number 1. Please try again.");
Console.Write("Type the number 1: ");
k = Console.ReadLine();
n = Convert.ToInt32(k);
q = Convert.ToBoolean(k);
}
}
Console.Write("Type the number 3: ");
l = Console.ReadLine();
r = Convert.ToBoolean(l);
o = Convert.ToInt32(l);
Console.WriteLine();
if (r <= 2 || r >= 4)
{
Console.WriteLine("Error: You didn't type the number 3. Please try again.");
Console.Write("Type the number 3: ");
l = Console.ReadLine();
r = Convert.ToBoolean(l);
o = Convert.ToInt32(l);
}
else
if (r = 3)
Console.WriteLine("Input accepted.");
Console.Write("Type the number 5: ");
m = Console.ReadLine();
p = Convert.ToInt32(m);
s = Convert.ToBoolean(m);
Console.WriteLine();
if (s <= 4 || s >= 6)
{
Console.WriteLine("Error: You didn't type the number 5. Please try again.");
Console.Write("Type the number 5: ");
m = Console.ReadLine();
p = Convert.ToInt32(m);
s = Convert.ToBoolean(m);
}
else
if (s = 5)
Console.WriteLine("Input accepted.");
firstTotal = n + o + p;
Console.WriteLine("{0} + {1} + {2} = {3}", n, o, p, firstTotal);
// Step 2: Entering integers for array[10]
int a, arrayTotal, b, c, d, e, f, g, h, i, j, unlimited;
Console.Write("Enter first integer for addition: ");
a = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter second integer for addition: ");
b = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter third integer for addition: ");
c = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter forth integer for addition: ");
d = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter fifth integer for addition: ");
e = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter sixth integer for addition: ");
f = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter seventh integer for addition: ");
g = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter eighth integer for addition: ");
h = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter ninth integer for addition: ");
i = Convert.ToInt32(Console.ReadLine());
Console.Write("Enter tenth integer for addition: ");
j = Convert.ToInt32(Console.ReadLine());
arrayTotal = a + b + c + d + e + f + g + h + i +j;
Console.WriteLine("The total of {0} + {1} + {2} + {3} + {4} + {5} + {6} + {7} + {8} + {9} = {10}",
a, b, c, d, e, f, g, h, i, j, arrayTotal);
// Step 3: Unlimited array addition
int[] arrayTwo;
int total, y;
string ADD, x;
while(Console.Write("Enter an integer for addition, or type ADD to calculate the sum: "))
{
x = Console.ReadLine();
y = Convert.ToInt32(x);
if (x == ADD)
Console.WriteLine("Calculating the total sum");
}
for (y = 0; y < arrayTwo.Length; ++y)
{
total = arrayTwo[y] + arrayTwo[y];
++arrayTwo[y];
Console.WriteLine("========================");
Console.WriteLine("=/n= The total is: {0} =/n=", total);
Console.WriteLine("========================");
}
}
}
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评论(4)
您不能在 C# 中编写
(q == 1)
,因为q
是bool
而1
是一个int
。q
只能与另一个布尔表达式进行比较,例如true
、false
、另一个布尔变量等。You can't write
(q == 1)
in C#, becauseq
is abool
and1
is anint
.q
can only be compared to another boolean expression, e.g.true
,false
, another boolean variable, etc.如果有人读到这个问题并需要将
bool
与int
进行比较:Just if someone read this question and needs comparing a
bool
with anint
:当我无意中使用 Visual Studio 2015 打开一个在 VS2017 中开发的解决方案时,我遇到了这个错误和许多其他错误。
其他错误包括:
;预期
} 预期
I got this error and many others when I inadvertently opened a solution with Visual Studio 2015 when it had been developed in VS2017.
Other errors included:
; expected
} expected
尝试使用
A.Equals(B)
而不是A == B
。Try to use
A.Equals(B)
instead ofA == B
.