构建、psycopg2、postgresql
我正在尝试制作从源代码安装 psycopg2 Egg 和 postgres 的构建配置如果需要:
parts =
...
postgre
psycopg2
...
[postgre]
recipe = hexagonit.recipe.cmmi
url = ftp://ftp3.ua.postgresql.org/pub/mirrors/postgresql/source/v9.0.0/postgresql-9.0.0.tar.gz
configure-options =
--without-readline
[psycopg2]
recipe = zc.recipe.egg:custom
egg = psycopg2
include-dirs =
${postgre:location}/include
library-dirs =
${postgre:location}/lib
rpath =
${postgre:location}/lib
问题是它总是从源代码构建 postgresql,即使用户已经安装了 postgresql。
我如何告诉 buildout 检查用户是否已经拥有构建 psycopg2 所需的所有内容?
I'm trying to make buildout config that installs psycopg2 egg and postgres from source if needed:
parts =
...
postgre
psycopg2
...
[postgre]
recipe = hexagonit.recipe.cmmi
url = ftp://ftp3.ua.postgresql.org/pub/mirrors/postgresql/source/v9.0.0/postgresql-9.0.0.tar.gz
configure-options =
--without-readline
[psycopg2]
recipe = zc.recipe.egg:custom
egg = psycopg2
include-dirs =
${postgre:location}/include
library-dirs =
${postgre:location}/lib
rpath =
${postgre:location}/lib
The problem is that it always builds postgresql from source, even if the user already has postgresql installed.
How can I tell buildout to check if user already have all necessary to build psycopg2?
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您可以做到这一点,但您必须制定自己的配方来进行检查。没有现有的食谱可以满足您的要求。
另一种方法是有两个构建配置。主
buildout.cfg
假设 postgresql 可用并且不会尝试构建它。第二个
withpostgres.cfg
可能如下所示:需要从源代码构建它的用户可以通过调用
bin/buildout -c withpostres.cfg
使用第二个配置。这能解决你的问题吗?
You can do it, but you'll have to make your own recipe to do that check. There's no existing recipe that does what you want.
An alternative is to have two buildout configs. The main
buildout.cfg
assumes postgresql is available and doesn't attempt to build it.A second
withpostgres.cfg
could look like this:Users that need to build it from source can use the second configuration by calling
bin/buildout -c withpostres.cfg
.Would that solve your issue?