bash 脚本将在 5 分钟内运行

发布于 2024-09-28 15:51:19 字数 135 浏览 3 评论 0原文

我只想让 bash 脚本在调用后运行 5 分钟。我做错了什么？

我有命令：

/path/to/my/script | at now + 5 min

但脚本每次都会立即运行。

原文

I just want a bash script to run 5 minutes after it's called. What am I doing wrong?

I have the command:

/path/to/my/script | at now + 5 min

And yet the script runs right away every time.

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生活了然无味 2024-10-05 15:51:19

您将立即执行脚本并将其输出发送到at。您需要将脚本本身的名称发送到at：

echo /path/to/my/script | at now + 5 min

You are executing the script immediately and sending its output into at. You need to send the name of the script itself into at:

echo /path/to/my/script | at now + 5 min

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烟花肆意 2024-10-05 15:51:19

怎么样：

sleep 300 && /path/to/my/script

how about:

sleep 300 && /path/to/my/script

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怪我鬧 2024-10-05 15:51:19

at -f /path/to/my/script -t now +5 minutes

这应该可以安排脚本在特定时间运行。有关“at”命令的更多信息，请尝试 linuxmanpages.com。我的想法可能是错误的（目前没有在linux系统上进行测试）。

无论如何祝你好运

at -f /path/to/my/script -t now +5 minutes

This should work as far as scheduling a script to run at a specific time. For any more information on the "at" command try linuxmanpages.com. I may be wrong thought ( currently not at a linux system to test ).

Good luck anyways

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笔芯 2024-10-05 15:51:19

问题是您正在运行脚本并将输出通过管道传输到 at 命令。您需要做的是运行 at 命令，并将脚本的路径作为参数。我不确定语法，但 at -h 或 man at 应该有帮助。

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红墙和绿瓦 2024-10-05 15:51:19

命令是从左到右评估的，因此首先执行您的脚本，其输出将通过管道传输到 at 命令，这是正常行为。有关详细信息，请参阅 at 手册页。

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甜味超标? 2024-10-05 15:51:19

试试这个

sys.scheduled_run /path/to/my/script 5

main function

function sys.scheduled_run(){
    local PATH_TO_ACTION MINS SLEEPTIME
    PATH_TO_ACTION=$1
    MINS=$2
    SLEEPTIME=$(($MINS * 60))
    echo "Sleeping for $MINS minute ($SLEEPTIME seconds) and then running $PATH_TO_ACTION"
    ui.countdown $SLEEPTIME
    $PATH_TO_ACTION
    echo "Done"
    if [ "REPEAT" == "$3" ] 
    then
        echo "Going for Repeat"
        sys.scheduled_run "$@"
    fi
}

倒计时功能

function ui.countdown(){ #USAGE ui.countdown 60 countdown for 60 seconds
        local SECONDS=$1
        local START=$(date +%s)
        local END=$((START + SECONDS))
        local CUR=$START
        while [[ $CUR -lt $END ]]
        do
                CUR=$(date +%s)
                LEFT=$((END-CUR))

                printf "\r%02d:%02d:%02d" \
                        $((LEFT/3600)) $(( (LEFT/60)%60)) $((LEFT%60))

                sleep 1
        done
        echo "        "
}

try this

sys.scheduled_run /path/to/my/script 5

main function

function sys.scheduled_run(){
    local PATH_TO_ACTION MINS SLEEPTIME
    PATH_TO_ACTION=$1
    MINS=$2
    SLEEPTIME=$(($MINS * 60))
    echo "Sleeping for $MINS minute ($SLEEPTIME seconds) and then running $PATH_TO_ACTION"
    ui.countdown $SLEEPTIME
    $PATH_TO_ACTION
    echo "Done"
    if [ "REPEAT" == "$3" ] 
    then
        echo "Going for Repeat"
        sys.scheduled_run "$@"
    fi
}

countdown function

function ui.countdown(){ #USAGE ui.countdown 60 countdown for 60 seconds
        local SECONDS=$1
        local START=$(date +%s)
        local END=$((START + SECONDS))
        local CUR=$START
        while [[ $CUR -lt $END ]]
        do
                CUR=$(date +%s)
                LEFT=$((END-CUR))

                printf "\r%02d:%02d:%02d" \
                        $((LEFT/3600)) $(( (LEFT/60)%60)) $((LEFT%60))

                sleep 1
        done
        echo "        "
}

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