帮助重构加载位图（而不是文件）到 PHP 服务器的工作方法

Question

这对于文件来说非常有用。我标记了需要重构的位置以使其能够与位图一起使用。我似乎找不到 .addPart 的兼容 ContentBody。

我试图解决的问题是，我已经在 Activity 的 ImageView 中拥有图像，因此我不想从 SD cara 再次读取它，而是想将其直接传递给此方法。当我这样做的时候，我可能会扩展它。

我在这段代码中找到了一条线索，但它似乎不符合 Android

    Part[] parts = {
            new FilePart("pictureFile", new 

ByteArrayPartSource("pictureFile", getBytes(位图))), };

我非常迷失:(

有什么想法吗？TIA。

public JSONArray uploadUserPhoto(String fileToSend,  boolean isPrimary) {

        String url = "http://www.nationwidearbitrationandmediation.com/ia/android/uploadImage.php"; 
        JSONArray jsonArray = null;

       try {
             HttpClient client = new DefaultHttpClient();  
             client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);

             HttpPost post = new HttpPost(url);
             //try adding these
             post.getParams().setParameter("http.protocol.expect-continue", false);
             post.getParams().setParameter("http.protocol.content-charset", "UTF-8"); 
             post.getParams().setParameter("http.protocol.reject-relative-redirect", false);

             MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);  

             reqEntity.addPart("ip", new StringBody(Boolean.toString(isPrimary), "text/plain", Charset.forName( "UTF-8" )));

               /***  NEED HELP HERE ****/
             File fileToUpload = new File(fileToSend);          //get file from name
             Log.d(TAG,"FileSize: " + fileToUpload.length());   //good time to test if file is larger than maxFileSize


             FileBody fileBody = new FileBody(fileToUpload, "image/jpg");
             reqEntity.addPart("uploadedfile", fileBody);
             /*****  DONE *****/

             post.setEntity(reqEntity);  

             HttpResponse response = client.execute(post);  
             HttpEntity resEntity = response.getEntity(); 
             String serverResponse = EntityUtils.toString(resEntity);
             client.getConnectionManager().shutdown();

             Log.i("RESPONSE",serverResponse);

             return  new JSONArray(serverResponse);

    } catch (Exception e) {
        Log.i(TAG,"Error: " + e.toString());
        return jsonArray;
    }

} //uploadUserPhoto

Answer 1

解决小图像 - 我使用 base64 编码使图像成为字符串。由于我只想要小图像，这对我有用。

我不会将此标记为已回答，因为其他人可能需要真正的修复而不是破解。

Answer 2

这是一个修改版本，它将字节数组发送到服务器，只要您可以获得图像字节，您就可以使用它将它们作为 POST 请求的附加图像发送到服务器：

public String uploadUserPhoto(byte[] bytesToSend,  boolean isPrimary) {
    String url = "test.php"; 

    try {
        HttpClient client = new DefaultHttpClient();  
        client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);

        HttpPost post = new HttpPost(url);
        //try adding these
        post.getParams().setParameter("http.protocol.expect-continue", false);
        post.getParams().setParameter("http.protocol.content-charset", "UTF-8"); 
        post.getParams().setParameter("http.protocol.reject-relative-redirect", false);

        MultipartEntity reqEntity = new MultipartEntity(HttpMultipartMode.BROWSER_COMPATIBLE);  

        reqEntity.addPart("ip", new StringBody(Boolean.toString(isPrimary), "text/plain", Charset.forName( "UTF-8" )));

        reqEntity.addPart(new FormBodyPart("uploadedFile", new ByteArrayBody(bytesToSend, "application/octet-stream", "uploadedFile"))); // you can also use image/jpg as mime type

        post.setEntity(reqEntity);  

        HttpResponse response = client.execute(post);  
        HttpEntity resEntity = response.getEntity(); 
        String serverResponse = EntityUtils.toString(resEntity);
        client.getConnectionManager().shutdown();


        return serverResponse;
    } catch (Exception e) {
        System.out.println("Error: " + e.toString());
        return null;
    }
}