表格布局中的 Drupal 形式

发布于 2024-09-28 13:50:24 字数 1016 浏览 8 评论 0原文

我正在尝试为表单呈现表格布局（html 表），以便第一个单元格包含一个复选框。

$form = array();
$res = query('SELECT * FROM {mytable}');
$rows = array();
while($row = db_fetch_array($res)){
    $record = array();
    $checkbox = array(
        '#type' => 'checkbox',
        '#attributes' => array(
            'value' => $row['id'],
            'name' => 'myrecord[]',
        ),
    ); 

    $record[] = drupal_render($checkbox);
    $record[] = $row['other_field_1'];
    $record[] = $row['other_field_2']
    $rows[] = $record;
}

$form['records'] = array(
    '#value' => theme('table', array(), $rows);
);

return $form;

但所有呈现的复选框都有输出

<input type="checkbox" class="form-checkbox" name="" value="1" id="">
<input type="checkbox" class="form-checkbox" name="" value="1" id="">
<input type="checkbox" class="form-checkbox" name="" value="1" id="">
<input type="checkbox" class="form-checkbox" name="" value="1" id="">

名称和值属性未应用于复选框的问题是什么？

原文

I am trying to render a tabular layout (html table) for a form such that first cell contains a checkbox.

$form = array();
$res = query('SELECT * FROM {mytable}');
$rows = array();
while($row = db_fetch_array($res)){
    $record = array();
    $checkbox = array(
        '#type' => 'checkbox',
        '#attributes' => array(
            'value' => $row['id'],
            'name' => 'myrecord[]',
        ),
    ); 

    $record[] = drupal_render($checkbox);
    $record[] = $row['other_field_1'];
    $record[] = $row['other_field_2']
    $rows[] = $record;
}

$form['records'] = array(
    '#value' => theme('table', array(), $rows);
);

return $form;

But all the rendered checkbox has output

<input type="checkbox" class="form-checkbox" name="" value="1" id="">
<input type="checkbox" class="form-checkbox" name="" value="1" id="">
<input type="checkbox" class="form-checkbox" name="" value="1" id="">
<input type="checkbox" class="form-checkbox" name="" value="1" id="">

What is the issue that name and value attributes are not getting applied on checkboxes?

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耳根太软 2024-10-05 13:50:24

使用表单 API 时，无法使用属性设置名称和值。该名称与表单项的键相关，因此如果您有

$form['pony'] = $checkbox;
$form['yes'] = $checkbox;

第一个复选框的名称将为pony，而第二个复选框的名称将为yes。我相信复选框的值始终为 1，但我不能 100% 确定。

要正确制作此表单，您应该做的就是仅在表单定义中创建表单。执行类似的操作：

$form = array();
$res = query('SELECT * FROM {mytable}');
while($row = db_fetch_array($res)){
  $form[$row['id']] = array('#tree' => TRUE);
  $form[$row['id']]['checkbox'] = array('#type' => 'checkbox');
  $form[$row['id']]['other_field_1'] = array('#value' => $row['other_field_1']);
  $form[$row['id']]['other_field_2'] = array('#value' => $row['other_field_1']);
}
return $form;

执行类似的操作，您可以在表单的主题函数中创建表。在主题函数中渲染表单元素，将为它们提供正确的名称。

The name and value is not something you can set using attributes, when using the form API. The name is related to the key of the form item, so if you had

$form['pony'] = $checkbox;
$form['yes'] = $checkbox;

The first checkbox will have the name of pony while the second will have the name of yes. I believe that the value for checkboxes always is 1, but I'm not 100% sure.

What you should do, to make this form properly, is to only create the form, in the form definition. Doing something like this:

$form = array();
$res = query('SELECT * FROM {mytable}');
while($row = db_fetch_array($res)){
  $form[$row['id']] = array('#tree' => TRUE);
  $form[$row['id']]['checkbox'] = array('#type' => 'checkbox');
  $form[$row['id']]['other_field_1'] = array('#value' => $row['other_field_1']);
  $form[$row['id']]['other_field_2'] = array('#value' => $row['other_field_1']);
}
return $form;

Doing something like this, you can create the table in a theme function for the form. Rendering the form elements in the theme function, will give them the correct name.

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