更改 ActionScript 2/3 上的纹理
有谁知道是否有一个简单的方法来改变它，
var colorTransform:NewColorTransform;
colorTransform = new NewColorTransform();
colorTransform.color = Config.ARRAY_COLOURS[1];
color.transform.colorTransform = colorTransform;
那就是改变颜色（ARRAY_COLOURS有[0xFF0000,0x0000FF,0xFFFF00]）
我想用像ARRAY_COLOURS[IMAGE1,IMAGE2,IMAGE3]这样的东西来代替
Does anybody knows if there is a simple way to change this
var colorTransform:NewColorTransform;
colorTransform = new NewColorTransform();
colorTransform.color = Config.ARRAY_COLOURS[1];
color.transform.colorTransform = colorTransform;
That is changing colors (the ARRAY_COLOURS have [ 0xFF0000, 0x0000FF, 0xFFFF00 ])
I would like to have instead of that something like ARRAY_COLOURS[ IMAGE1, IMAGE2, IMAGE3 ]
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我们需要更多信息才能为您提供更准确的答案。
无论如何，你可能可以做这样的事情
private var bitmaps:Array = [image1 , image2 , image3]; private var colours:Array = [colour1 , colour2 , colour3]; private var textureTransform:String; private var selectedBitmap:Bitmap; private function init():void { switch ( textureTransform ) { case 'bitmap': selectedBitmap = bitmaps[1]; bitmapChange(); break; case 'colour': //the example in your question colourTransform(); break; } } private function bitmapChange():void { this.addChild( selectedBitmap ); }We would need more info in order to give you a more accurate answer.
In any case, you probably could do something like this
private var bitmaps:Array = [image1 , image2 , image3]; private var colours:Array = [colour1 , colour2 , colour3]; private var textureTransform:String; private var selectedBitmap:Bitmap; private function init():void { switch ( textureTransform ) { case 'bitmap': selectedBitmap = bitmaps[1]; bitmapChange(); break; case 'colour': //the example in your question colourTransform(); break; } } private function bitmapChange():void { this.addChild( selectedBitmap ); }