javax.xml.parsers.DocumentBuilder 对复杂类型的支持
我正在尝试整理一些验证代码。我正在尝试验证类似的模式:
<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:ecore="http://www.eclipse.org/emf/2002/Ecore" xmlns:choice="http://example.com/SimpleChoice" targetNamespace="http://example.com/SimpleChoice" ecore:nsPrefix="choice" ecore:package="com.example.simple.choice">
<xsd:complexType name="Plane">
<xsd:sequence>
<xsd:element name="freightDetails" type="xsd:string" minOccurs="0"/>
<xsd:element name="passengers" type="xsd:int" minOccurs="0"/>
</xsd:sequence>
</xsd:complexType>
</xsd:schema>
使用以下 XML:
<?xml version="1.0" encoding="UTF-8"?>
<choice:Plane xmlns:choice="http://example.com/SimpleChoice">
<freightDetails>Boxes</freightDetails>
</choice:Plane>
它似乎抱怨没有元素,但我正在尝试找到一种方法来验证类型。我收到以下错误:
[Error] :1:100: cvc-elt.1: Cannot find the declaration of element 'choice:Plane'.
当它尝试使用以下代码加载文档时:
SchemaFactory factory =
SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = factory.newSchema(schemaFile);
DocumentBuilderFactory parserFactory = DocumentBuilderFactory.newInstance();
parserFactory.setSchema(schema);
parserFactory.setNamespaceAware(true);
DocumentBuilder parser = parserFactory.newDocumentBuilder();
Document document = parser.parse(inputSource);
Validator validator = schema.newValidator();
validator.validate(new DOMSource(document));
当它到达: 时失败:
Document document = parser.parse(inputSource);
有谁知道我如何才能使其工作? (或者支持这种行为的验证器?)
谢谢
Rob
I'm trying to put together some validation code. I am trying to validate against a schema like:
<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:ecore="http://www.eclipse.org/emf/2002/Ecore" xmlns:choice="http://example.com/SimpleChoice" targetNamespace="http://example.com/SimpleChoice" ecore:nsPrefix="choice" ecore:package="com.example.simple.choice">
<xsd:complexType name="Plane">
<xsd:sequence>
<xsd:element name="freightDetails" type="xsd:string" minOccurs="0"/>
<xsd:element name="passengers" type="xsd:int" minOccurs="0"/>
</xsd:sequence>
</xsd:complexType>
</xsd:schema>
With the following XML:
<?xml version="1.0" encoding="UTF-8"?>
<choice:Plane xmlns:choice="http://example.com/SimpleChoice">
<freightDetails>Boxes</freightDetails>
</choice:Plane>
It seems to complain that there is no element, but I'm trying to find a way to validate against the type. I get the following error:
[Error] :1:100: cvc-elt.1: Cannot find the declaration of element 'choice:Plane'.
When it tries to load the document with the following code:
SchemaFactory factory =
SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI);
Schema schema = factory.newSchema(schemaFile);
DocumentBuilderFactory parserFactory = DocumentBuilderFactory.newInstance();
parserFactory.setSchema(schema);
parserFactory.setNamespaceAware(true);
DocumentBuilder parser = parserFactory.newDocumentBuilder();
Document document = parser.parse(inputSource);
Validator validator = schema.newValidator();
validator.validate(new DOMSource(document));
It fails when it gets to the:
Document document = parser.parse(inputSource);
Does anyone have any ideas on how I would be able to get this working? (Or a validator that supports this sort of behaviour?)
Thanks
Rob
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这是因为您的架构已定义类型 (
Plane
),但尚未定义任何允许使用该类型的元素。类型本身在模式本身之外没有任何意义。您需要将
添加到架构中。最简单的解决方案是在其中使用匿名复杂类型,例如:This is because your schema has defined a type (
Plane
), but hasn't defined any permitted elements that use that type. A type on its own has no meaning outside of the schema itself.You need to add an
<xsd:element>
to your schema. The simplest solution is to use an anonymous complex type within that, something like:在您的示例架构中,您仅定义了名为
Plane
的类型,而不是名为Plane
的元素。将元素声明添加到您的架构中,看看会发生什么......In your example schema, you have only defined a type named
Plane
, not an element namedPlane
. Add an element declaration to your schema and see what happens...