根据 NSArray / NSDictionary 层次结构中的其他对象检索对象

发布于 2024-09-27 14:16:30 字数 527 浏览 7 评论 0原文

抱歉这个奇怪的标题......一切都会得到解释。

基本上我的应用程序中有一个像这样的数组/字典结构：

NSArray {

    NSDictionary {
        (NSString *)id;
        (NSDictionary *)dictionary;
    }

    NSDictionary {
        (NSString *)id;
        (NSDictionary *)dictionary;
    }

    NSDictionary {
        (NSString *)id;
        (NSDictionary *)dictionary;
    }

    etc...

}

希望这很容易解决...

现在我有一个 (NSString *)id 并且我想获取 (NSDictionary *)与之对应的字典。

有什么办法可以做到这一点吗？

谢谢

汤姆

原文

Sorry about the weird title... all will be explained.

Basically I have an array/dictionary structure like this in my app:

NSArray {

    NSDictionary {
        (NSString *)id;
        (NSDictionary *)dictionary;
    }

    NSDictionary {
        (NSString *)id;
        (NSDictionary *)dictionary;
    }

    NSDictionary {
        (NSString *)id;
        (NSDictionary *)dictionary;
    }

    etc...

}

Hope that's easy to work out...

Now I have an (NSString *)id and I want to get the (NSDictionary *)dictionary which corresponds to it.

Is there any way that I can do this?

Thank you

Tom

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星星的轨迹 2024-10-04 14:16:30

尝试这样的事情

for (NSDictionary *dict in dictArray) {
    if ([[dict objectForKey:@"id"] isEqualToString:targetID]){
        return [dict objectForKey:@"dictionary"];
    }
}

我还没有编译代码（我附近没有mac），但我想你明白了。基本思想是循环遍历数组并比较查询字符串。但如果您有很多项目，那么这种线性搜索可能会很耗时。

Try something like this

for (NSDictionary *dict in dictArray) {
    if ([[dict objectForKey:@"id"] isEqualToString:targetID]){
        return [dict objectForKey:@"dictionary"];
    }
}

I have not compiled the code(don't have mac near me), but I think you got the idea. The basic idea is to loop through the array and compare query string. But if you have many items then this linear search might be time consuming.

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