VB.Net 中的布尔表 - Select Case、If-Else 还是其他?
我正在寻求简化三项布尔表达式的处理。 “Select Case”似乎没有提供三重值的解决方案,并且 If 语句似乎有点多。它将按照我编码的方式工作,但如果您对如何简化它有任何想法,我将不胜感激您的见解。如果没有,我希望这个片段可以节省其他人一点时间。
Public Sub SetThisFontStyle(ByRef theTextBox As RichTextBox, ByVal StyleToChange As String)
'Get Initial Values:'
Dim BoldState As Boolean = theTextBox.SelectionFont.Bold
Dim ItalicState As Boolean = theTextBox.SelectionFont.Italic
Dim UnderlineState As Boolean = theTextBox.SelectionFont.Underline
'Find out what we re trying to change:'
Select Case StyleToChange
Case "Bold" : If BoldState Then BoldState = False Else BoldState = True
Case "Italic" : If ItalicState Then ItalicState = False Else ItalicState = True
Case "Underline" : If UnderlineState Then UnderlineState = False Else UnderlineState = True
Case Else : Exit Sub
End Select
'Boolean Table just for reference:'
'0 - 0 - 0 None'
'1 - 0 - 0 Bold Only'
'0 - 1 - 0 Italic Only'
'0 - 0 - 1 Underline Only'
'1 - 1 - 0 Bold and Italic'
'0 - 1 - 1 Italic and Underline '
'1 - 0 - 1 Bold and Underline'
'1 - 1 - 1 Bold, Italic, and Underline'
If Not BoldState And Not ItalicState And Not UnderlineState Then
'Regular, without any styles'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Regular)
ElseIf BoldState And Not ItalicState And Not UnderlineState Then
'Bold Only'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold)
ElseIf Not BoldState And ItalicState And UnderlineState Then
'Italic Only'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Italic)
ElseIf Not BoldState And Not ItalicState And UnderlineState Then
'Underline Only'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Underline)
ElseIf BoldState And ItalicState And Not UnderlineState Then
'Bold and Italic'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold + Drawing.FontStyle.Italic)
ElseIf Not BoldState And ItalicState And UnderlineState Then
'Italic and Underline'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Italic + Drawing.FontStyle.Underline)
ElseIf BoldState And Not ItalicState And UnderlineState Then
'Bold and Underline'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold + Drawing.FontStyle.Underline)
ElseIf BoldState And ItalicState And UnderlineState Then
'Bold, Italic, and Underline'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold + Drawing.FontStyle.Italic + Drawing.FontStyle.Underline)
Else
Exit Sub
End If
End Sub
I'm looking to simplify the handling of a three-item Boolean expression. "Select Case" doesn't seem offer a solution for triple values, and the If statement seems a bit much. It'll work the way I coded it, but if you have any ideas on how to simplify this, I'd appreciate your insights. If not, I hope this snippet can save someone else a little time.
Public Sub SetThisFontStyle(ByRef theTextBox As RichTextBox, ByVal StyleToChange As String)
'Get Initial Values:'
Dim BoldState As Boolean = theTextBox.SelectionFont.Bold
Dim ItalicState As Boolean = theTextBox.SelectionFont.Italic
Dim UnderlineState As Boolean = theTextBox.SelectionFont.Underline
'Find out what we re trying to change:'
Select Case StyleToChange
Case "Bold" : If BoldState Then BoldState = False Else BoldState = True
Case "Italic" : If ItalicState Then ItalicState = False Else ItalicState = True
Case "Underline" : If UnderlineState Then UnderlineState = False Else UnderlineState = True
Case Else : Exit Sub
End Select
'Boolean Table just for reference:'
'0 - 0 - 0 None'
'1 - 0 - 0 Bold Only'
'0 - 1 - 0 Italic Only'
'0 - 0 - 1 Underline Only'
'1 - 1 - 0 Bold and Italic'
'0 - 1 - 1 Italic and Underline '
'1 - 0 - 1 Bold and Underline'
'1 - 1 - 1 Bold, Italic, and Underline'
If Not BoldState And Not ItalicState And Not UnderlineState Then
'Regular, without any styles'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Regular)
ElseIf BoldState And Not ItalicState And Not UnderlineState Then
'Bold Only'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold)
ElseIf Not BoldState And ItalicState And UnderlineState Then
'Italic Only'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Italic)
ElseIf Not BoldState And Not ItalicState And UnderlineState Then
'Underline Only'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Underline)
ElseIf BoldState And ItalicState And Not UnderlineState Then
'Bold and Italic'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold + Drawing.FontStyle.Italic)
ElseIf Not BoldState And ItalicState And UnderlineState Then
'Italic and Underline'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Italic + Drawing.FontStyle.Underline)
ElseIf BoldState And Not ItalicState And UnderlineState Then
'Bold and Underline'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold + Drawing.FontStyle.Underline)
ElseIf BoldState And ItalicState And UnderlineState Then
'Bold, Italic, and Underline'
theTextBox.SelectionFont = _
New Font(txtRichText.SelectionFont, Drawing.FontStyle.Bold + Drawing.FontStyle.Italic + Drawing.FontStyle.Underline)
Else
Exit Sub
End If
End Sub
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我将使用带有 [Flags] 属性的枚举,然后您可以检查组合。它还将使代码更具可读性。
对于 C# 感到抱歉,不知道如何将其转换为 VB.Net
I would use an Enum with the [Flags] attribute and then you can check combinations. It would also make the code more readable.
Sorry about the C#, not sure how to translate that to VB.Net