来自 php 的 Cron 作业（准确地说是 at 命令）
我想通过使用“at”命令设置 cron 作业来运行脚本一次。 我现在正在使用这个：
<?php
include "config.php";
if (isset($_POST['add']))
{
$sql = mysql_query("INSERT INTO {$table}(msg) VALUES('{$_POST['msg']}')");
if ($sql)
{
$cmd = "wget /var/www/index.php?id=" . mysql_insert_id() . " | sudo at " . $_POST['runat'];
exec($cmd);
echo exec("atq");
echo $cmd;
}
exit();
}
echo "<form action='{$_SERVER['PHP_SELF']}' method='POST'>";
echo "<input type='text' name='msg' />";
echo "<input type='text' name='runat' />";
echo "<input type='submit' name='add' />";
echo "</form>";
?>
但是，这似乎不起作用。我这样做对吗？或者你能推荐别的东西吗？
I want to run a script just ONCE by setting up a cron job using "at" command.
I'm using this now:
<?php
include "config.php";
if (isset($_POST['add']))
{
$sql = mysql_query("INSERT INTO {$table}(msg) VALUES('{$_POST['msg']}')");
if ($sql)
{
$cmd = "wget /var/www/index.php?id=" . mysql_insert_id() . " | sudo at " . $_POST['runat'];
exec($cmd);
echo exec("atq");
echo $cmd;
}
exit();
}
echo "<form action='{$_SERVER['PHP_SELF']}' method='POST'>";
echo "<input type='text' name='msg' />";
echo "<input type='text' name='runat' />";
echo "<input type='submit' name='add' />";
echo "</form>";
?>
However, this doesn't seem to be working. Am I doing this right? Or could you recommend something else?
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您以错误的方式使用
at命令。您需要回显命令并将其传递给at。像这样尝试一下：You are using
atcommand in wrong way. You need to echo command and pass it toat. Try it like that: