检查 UI_USER_INTERFACE_IDIOM() 以确定它是 iPhone 还是 iPad 是否安全？
我在此处找到了此代码：
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
str = [NSString stringWithString:@"Running as an iPad application"];
} else {
str = [NSString stringWithString:
@"Running as an iPhone/iPod touch application"];
}
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Platform"
message:str
delegate:nil
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
[alert release];
此检查有多安全？苹果真的建议这样做吗？或者它不会将 iPad 检测为 iPad，或将 iPhone 检测为 iPhone？
I've found this code, here:
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {
str = [NSString stringWithString:@"Running as an iPad application"];
} else {
str = [NSString stringWithString:
@"Running as an iPhone/iPod touch application"];
}
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Platform"
message:str
delegate:nil
cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alert show];
[alert release];
How safe is this check? Does Apple actually recommend doing this? Or can it happen that it won't detect an iPad as iPad, or iPhone as iPhone?
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它应该足够安全，很好-由 Apple 记录。
这只是以下代码的简写：
如果您尝试在低于 iOS 3.2 的系统上运行此代码（因为当时才引入），它可能会失败，但这对您来说可能不是问题。
It should be safe enough, it's well-documented by Apple.
That is just shorthand for the following code:
It could conceivably fail if you tried to run this on anything less than iOS 3.2 (as it was only introduced then), but this might not be an issue for you.