在 WPF 中，如何在保留键盘快捷键的同时右对齐菜单项？
我最近更改了我的 XAML，以获得右对齐菜单项的功能，例如在下图中设置字体大小：
File Configure Help
+-------------+ +----+
| Font size > |->| 8 |
| Speed > | | 10 |
+-------------+ | 12 |
+----+
显然，基于该图形，我不会很快从技术角色转向图形设计： -）这只是为了说明我的意思。
下面的原始 XAML 没有右对齐值
<MenuItem Header="_Configure">
<MenuItem Header="_Font size ">
<MenuItem Header="_8" Click="menuConfigFontSz8" />
<MenuItem Header="1_0" Click="menuConfigFontSz10" />
<MenuItem Header="1_2" Click="menuConfigFontSz12" />
</MenuItem>
:
</MenuItem>
而是给了我：
File Configure Help
+-------------+ +----+
| Font size > |->| 8 |
| Speed > | | 10 |
+-------------+ | 12 |
+----+
因此，为了获得右对齐，我将其更改为：
<MenuItem Header="_Configure">
<MenuItem Header="_Font size ">
<MenuItem Click="menuConfigFontSz8">
<MenuItem.Header>
<TextBlock HorizontalAlignment="Right">_8</TextBlock>
</MenuItem.Header>
</MenuItem>
<MenuItem Click="menuConfigFontSz10">
<MenuItem.Header>
<TextBlock HorizontalAlignment="Right">1_0</TextBlock>
</MenuItem.Header>
</MenuItem>
<MenuItem Click="menuConfigFontSz12">
<MenuItem.Header>
<TextBlock HorizontalAlignment="Right">1_2</TextBlock>
</MenuItem.Header>
</MenuItem>
</MenuItem>
:
</MenuItem>
但是，我发现我已经失去了执行 AltC、F、0 用于选择字体大小 10（只是 0 位不再起作用，前两位仍然没问题）。
相反，它在菜单本身中为我提供了文字文本 1_0，而不是允许我使用 0 作为选择项目的快速方法：
File Configure Help
+-------------+ +-----+
| Font size > |->| _8 |
| Speed > | | 1_0 |
+-------------+ | 1_2 |
+-----+
How do I keep the right justification菜单文本但仍然允许加速器？
I recently changed my XAML in order to gain the capability to right-justify menu items such as setting font sizes in the below graphic:
File Configure Help
+-------------+ +----+
| Font size > |->| 8 |
| Speed > | | 10 |
+-------------+ | 12 |
+----+
Obviously, based on that graphic, I won't be moving from a technical role into graphic design anytime soon :-) It's more just to illustrate what I meant.
The original XAML below did not right-justify the values
<MenuItem Header="_Configure">
<MenuItem Header="_Font size ">
<MenuItem Header="_8" Click="menuConfigFontSz8" />
<MenuItem Header="1_0" Click="menuConfigFontSz10" />
<MenuItem Header="1_2" Click="menuConfigFontSz12" />
</MenuItem>
:
</MenuItem>
Instead, it gave me:
File Configure Help
+-------------+ +----+
| Font size > |->| 8 |
| Speed > | | 10 |
+-------------+ | 12 |
+----+
So, to get right-justification, I changed it to:
<MenuItem Header="_Configure">
<MenuItem Header="_Font size ">
<MenuItem Click="menuConfigFontSz8">
<MenuItem.Header>
<TextBlock HorizontalAlignment="Right">_8</TextBlock>
</MenuItem.Header>
</MenuItem>
<MenuItem Click="menuConfigFontSz10">
<MenuItem.Header>
<TextBlock HorizontalAlignment="Right">1_0</TextBlock>
</MenuItem.Header>
</MenuItem>
<MenuItem Click="menuConfigFontSz12">
<MenuItem.Header>
<TextBlock HorizontalAlignment="Right">1_2</TextBlock>
</MenuItem.Header>
</MenuItem>
</MenuItem>
:
</MenuItem>
However, I find I've lost the shortcut capability of doing AltC, F, 0 for selecting font size 10 (it's just the 0 bit that no longer works, the first two bits are still fine).
Instead it gives me the literal text 1_0 in the menu itself rather than allowing me to use 0 as a quick way of selecting the item:
File Configure Help
+-------------+ +-----+
| Font size > |->| _8 |
| Speed > | | 1_0 |
+-------------+ | 1_2 |
+-----+
How do I keep the right justification of the menu text but still allow for an accelerator?
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当您向 MenuItem（和 Button）添加加速器时，WPF 会自动向您的 MenuItem 添加 TextBlock，这可能会阻止您的代码工作。如果您查看回答此问题。
如果您的资源中没有覆盖默认 TextBlock 行为的通用 TextBlock 样式，则此代码可以解决该问题。
When you add an accelerator to a MenuItem (and Button) WPF automatically adds a TextBlock to your MenuItem, and this probably prevents your code from working. You can see this effect if you take a look at the answer to this question.
This code solves the problem if you do not have a generic TextBlock style in your resources that overrides the default TextBlock behaviour.