访问 Cucumber 中的控制器以测试登录

发布于 2024-09-26 21:38:35 字数 619 浏览 0 评论 0原文

首先 - 我知道这通常是可怕的做法,因为 Cucumber 只用于测试输出。我只想针对一个非常非常具体的案例执行此操作。

我有一个应用程序,它使用我维护的另一个应用程序设置的 cookie 来处理用户身份验证。我想编写一个非常简单的身份验证集成测试:

Given I have logged as "some_user" on the SSO server
When I visit any page
Then I should be logged in as "some_user"

我当前的“Then”步骤定义如下:

Then /^I should be logged in as "([^"]*)"$/ do |username|
  user = User.find_by_username(username)
  assert_equal @controller.current_user, user
end

显然,这因“Undefined method 'current_user' for nil:NilClass”而失败。

如果不明显 - ApplicationController#current_user 返回当前登录的用户或 nil。

First off - I know that this is generally horrible practice, because Cucumber is meant to only test outputs. I just want to do this for one veryveryvery specific case.

I have an app that handles user authentication using a cookie set by another app I maintain. I'd like to write a very simple integration test for authentication:

Given I have logged as "some_user" on the SSO server
When I visit any page
Then I should be logged in as "some_user"

My current step definition for the Then is as follows:

Then /^I should be logged in as "([^"]*)"$/ do |username|
  user = User.find_by_username(username)
  assert_equal @controller.current_user, user
end

Obviously, this is failing with "Undefined method 'current_user' for nil:NilClass".

In case it's not obvious - ApplicationController#current_user returns either the user currently logged in or nil.

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扬花落满肩 2024-10-03 21:38:35

您可以访问显示当前登录用户名的某些页面。
喜欢:
当我进入帐户页面时
然后我应该在“div#login”中看到“欢迎用户”

You can visit some page where currently logged on user's name is displayed.
Like:
When I go to the account page
Then I should see "Welcome user" within "div#login"

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