在 BufferedImage 中绘制多条线

Question

我正在尝试在缓冲图像上绘制水平线和垂直线。它最终应该看起来像一个细胞网格。但是当我运行代码时，我只看到两行：最左边的行和最上面的行（即从 0,0 到 0,图像高度 & 0,0 到图像宽度,0 的一行）下面是代码代码片段：

  BufferedImage mazeImage = new BufferedImage(imgDim.width, imgDim.height, BufferedImage.TYPE_INT_RGB);
  Graphics2D g2d = mazeImage.createGraphics();
  g2d.setBackground(Color.WHITE);
  g2d.fillRect(0, 0, imgDim.width, imgDim.height);
  g2d.setColor(Color.BLACK);
  BasicStroke bs = new BasicStroke(2);
  g2d.setStroke(bs);
  // draw the black vertical and horizontal lines
  for(int i=0;i<21;i++){
   g2d.drawLine((imgDim.width+2)*i, 0, (imgDim.width+2)*i,  imgDim.height-1);
   g2d.drawLine(0, (imgDim.height+2)*i, imgDim.width-1, (imgDim.height+2)*i);
  }

以及重写的绘制方法：

public void paint(Graphics g) {
  g.drawImage(mazeImage, 0, 0, this);
}

这一切都在一个名为 RobotMaze 的类中，该类扩展了 JPanel。任何帮助表示赞赏。

Answer 1

import java.awt.*;
import java.awt.image.*;
import javax.swing.*;

class GridLines {

    public static void main(String[] args) {

        Dimension imgDim = new Dimension(200,200);
        BufferedImage mazeImage = new BufferedImage(imgDim.width, imgDim.height, BufferedImage.TYPE_INT_RGB);


        Graphics2D g2d = mazeImage.createGraphics();
        g2d.setBackground(Color.WHITE);
        g2d.fillRect(0, 0, imgDim.width, imgDim.height);
        g2d.setColor(Color.BLACK);
        BasicStroke bs = new BasicStroke(2);
        g2d.setStroke(bs);
        // draw the black vertical and horizontal lines
        for(int i=0;i<21;i++){
            // unless divided by some factor, these lines were being
            // drawn outside the bound of the image..
            g2d.drawLine((imgDim.width+2)/20*i, 0, (imgDim.width+2)/20*i,imgDim.height-1);
            g2d.drawLine(0, (imgDim.height+2)/20*i, imgDim.width-1, (imgDim.height+2)/20*i);
        }

        ImageIcon ii = new ImageIcon(mazeImage);
        JOptionPane.showMessageDialog(null, ii);
    }
}

Answer 2

打印出您的坐标，您将看到您正在绘制图像宽度和高度之外的点：

System.out.printf("Vertical: (%d,%d)->(%d,%d)\n",(imgDim.width+2)*i, 0, (imgDim.width+2)*i,  imgDim.height-1);
System.out.printf("Horizontal: (%d,%d)->(%d,%d)\n",0, (imgDim.height+2)*i, imgDim.width-1, (imgDim.height+2)*i);

Answer 3

如果 i > (imgDim.width+2)*i 的结果如何在图像边界内？ 0？