为什么我没有收到 Spring Security 登录错误消息？

Question

使用 Spring Security 3 以及 Struts 2 和 Tiles 2，我有一个登录页面，该页面会在应该出现时出现并按预期执行登录 - 但是，当我输入错误的用户凭据时，我会返回到登录页面，但没有有关的信息出了什么问题。我检查了所有配置参数，但看不出问题出在哪里。

我的 Spring Security XML 配置如下：

 <http auto-config="true" use-expressions="true">
    <intercept-url pattern="/" access="permitAll" />
    <intercept-url pattern="/css/**" access="permitAll" />
    <intercept-url pattern="/images/**" access="permitAll" />
    <intercept-url pattern="/js/**" access="permitAll" />
    <intercept-url pattern="/public/**" access="permitAll" />
    <intercept-url pattern="/home/**" access="permitAll" />
    <intercept-url pattern="/user/**" access="hasRole('AUTH_MANAGE_USERS')" />
    <intercept-url pattern="/group/**" access="hasRole('AUTH_MANAGE_USERS')" />
    <intercept-url pattern="/**" access="isAuthenticated()" />
    <access-denied-handler error-page="/403.html"/>
    <form-login  login-page="/public/login.do" always-use-default-target="false"/>
    <logout invalidate-session="true" logout-success-url="/public/home.do"/>
</http>

我的 Struts Action 如下所示：

<package name="public" namespace="/public" extends="secure">
    <action name="login">
        <result name="success" type="tiles">tiles.login.panel</result>
        <result name="input" type="tiles">tiles.login.panel</result>
        <result name="error">/WEB-INF/jsp/error.jsp</result>
    </action>
    <action name="logout">
        <result name="success" type="redirect">/j_spring_security_logout</result>
    </action>
</package>

Login.jsp 页面（图块的一部分）查找 Spring Security 的异常...

<c:if test="${not empty param.login_error}">
   <span class="actionError">
   Your login attempt was not successful, try again.<br/><br/>
        Reason: <c:out value="${SPRING_SECURITY_LAST_EXCEPTION.message}"/>.
  </span>
</c:if>
<form id="loginForm" name="loginForm" action="/j_spring_security_check" method="post">
  ...
</form>

谁能告诉我缺少什么？预先感谢您的任何/所有回复。

Answer 1

Spring Security 不会自动设置 param.login_error 。您需要手动执行以下操作：

<form-login  
    login-page="/public/login.do" 
    authentication-failure-url = "/public/login.do?login_error=1"
    always-use-default-target="false"/>

Answer 2

帮助转换错误消息（如最后评论中）的一个建议是使用 AuthenticationFailureHandler 将不同的异常类型映射到 ui 层代码可以查找唯一消息的不同错误代码。它看起来像：

<security:form-login login-page="/login" 
    authentication-failure-handler-ref="authenticationFailureHandler"/>

<bean id="authenticationFailureHandler" class="org.springframework.security.web.authentication.ExceptionMappingAuthenticationFailureHandler">
    <property name="defaultFailureUrl" value="/login?reason=login_error"/>
    <property name="exceptionMappings">
        <map>
        <entry><key><value>org.springframework.security.authentication.LockedException</value></key>
            <value>/login?reason=user_locked</value></entry>

            <entry><key><value>org.springframework.security.authentication.DisabledException</value></key>
            <value>/login?reason=user_disabled</value></entry>

            <entry><key><value>org.springframework.security.authentication.AuthenticationServiceException</value></key>
            <value>/login?reason=connection</value></entry>
        </map>
    </property>
</bean>