如何从 Uri 获取位图?

发布于 2024-09-26 14:47:29 字数 173 浏览 1 评论 0原文

如何从 Uri 获取 Bitmap 对象(如果我成功将其存储在 /data/data/MYFOLDER/myimage.pngfile///data/data/MYFOLDER/myimage.png) 在我的应用程序中使用它?

有谁知道如何实现这一目标?

How to get a Bitmap object from an Uri (if I succeed to store it in
/data/data/MYFOLDER/myimage.png or file///data/data/MYFOLDER/myimage.png) to use it in my application?

Does anyone have an idea on how to accomplish this?

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评论(24

撑一把青伞 2024-10-03 14:47:30

(科特林)
因此,截至 2020 年 4 月 7 日,上述选项均不起作用,但以下是对我有用的选项:

  1. 如果您想将位图存储在 val 中并用它设置 imageView,请使用此:

    val bitmap = BitmapFactory.decodeFile(currentPhotoPath).also { 位图 -> imageView.setImageBitmap(bitmap) }

  2. 如果您只想将位图设置为 imageView,请使用:

    BitmapFactory.decodeFile(currentPhotoPath).also { 位图 -> imageView.setImageBitmap(bitmap) }

(KOTLIN)
So, as of April 7th, 2020 none of the above mentioned options worked, but here's what worked for me:

  1. If you want to store the bitmap in a val and set an imageView with it, use this:

    val bitmap = BitmapFactory.decodeFile(currentPhotoPath).also { bitmap -> imageView.setImageBitmap(bitmap) }

  2. If you just want to set the bitmap to and imageView, use this:

    BitmapFactory.decodeFile(currentPhotoPath).also { bitmap -> imageView.setImageBitmap(bitmap) }

屋檐 2024-10-03 14:47:30
* For getting bitmap from uri. Work for me perfectly.
    
    
    public static Bitmap decodeUriToBitmap(Context mContext, Uri sendUri) {
          Bitmap getBitmap = null;
          try {
            InputStream image_stream;
            try {
              image_stream = mContext.getContentResolver().openInputStream(sendUri);
              getBitmap = BitmapFactory.decodeStream(image_stream);
            } catch (FileNotFoundException e) {
              e.printStackTrace();
            }
          } catch (Exception e) {
            e.printStackTrace();
          }
          return getBitmap;
        }
* For getting bitmap from uri. Work for me perfectly.
    
    
    public static Bitmap decodeUriToBitmap(Context mContext, Uri sendUri) {
          Bitmap getBitmap = null;
          try {
            InputStream image_stream;
            try {
              image_stream = mContext.getContentResolver().openInputStream(sendUri);
              getBitmap = BitmapFactory.decodeStream(image_stream);
            } catch (FileNotFoundException e) {
              e.printStackTrace();
            }
          } catch (Exception e) {
            e.printStackTrace();
          }
          return getBitmap;
        }
战皆罪 2024-10-03 14:47:30

从移动图库获取图像 uri 的完整方法。

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

  if (requestCode == PICK_IMAGE_REQUEST && resultCode == RESULT_OK && data != null && data.getData() != null) {
                Uri filePath = data.getData();

     try { //Getting the Bitmap from Gallery
           Bitmap bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
           rbitmap = getResizedBitmap(bitmap, 250);//Setting the Bitmap to ImageView
           serImage = getStringImage(rbitmap);
           imageViewUserImage.setImageBitmap(rbitmap);
      } catch (IOException e) {
           e.printStackTrace();
      }


   }
}

Full method to get image uri from mobile gallery.

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

  if (requestCode == PICK_IMAGE_REQUEST && resultCode == RESULT_OK && data != null && data.getData() != null) {
                Uri filePath = data.getData();

     try { //Getting the Bitmap from Gallery
           Bitmap bitmap = MediaStore.Images.Media.getBitmap(getContentResolver(), filePath);
           rbitmap = getResizedBitmap(bitmap, 250);//Setting the Bitmap to ImageView
           serImage = getStringImage(rbitmap);
           imageViewUserImage.setImageBitmap(rbitmap);
      } catch (IOException e) {
           e.printStackTrace();
      }


   }
}
傾旎 2024-10-03 14:47:30

我使用此处提供的解决方案时遇到的一个反复出现的问题是:

无法找到提供商信息
com.samsung.systemui.navillera.navilleraprovider

这将阻止加载您的位图。

我尝试了这个,它有效!赞美神。

解释是提供的uri需要转换成文件路径。

Bitmap b1 = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.fromFile(new File(uri1.toString())));

A recurring problem that I faced using the solutions provided here is:

Failed to find provider info for
com.samsung.systemui.navillera.navilleraprovider

This will prevent your bitmap from being loaded.

I tried this instead and it works! Praise God.

The explanation is that the uri provided needs to be converted into a file path.

Bitmap b1 = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.fromFile(new File(uri1.toString())));
筑梦 2024-10-03 14:47:30

在 2022 年,为此目的使用线圈库。

https://coil-kt.github.io/线圈/组合/

用于喷气背包组合

            AsyncImage(
                model = uriOfImage,
                contentDescription = null,
            )

Use coil libray for this purpose on 2022.

https://coil-kt.github.io/coil/compose/

for jetpack compose

            AsyncImage(
                model = uriOfImage,
                contentDescription = null,
            )
若言繁花未落 2024-10-03 14:47:29

这是正确的方法:

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
    super.onActivityResult(requestCode, resultCode, data);
    if (resultCode == RESULT_OK)
    {
        Uri imageUri = data.getData();
        Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
    }
}

如果您需要加载非常大的图像,以下代码会将其加载到图块中(避免大量内存分配):

BitmapRegionDecoder decoder = BitmapRegionDecoder.newInstance(myStream, false);  
Bitmap region = decoder.decodeRegion(new Rect(10, 10, 50, 50), null);

请参阅答案 这里

Here's the correct way of doing it:

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
    super.onActivityResult(requestCode, resultCode, data);
    if (resultCode == RESULT_OK)
    {
        Uri imageUri = data.getData();
        Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
    }
}

If you need to load very large images, the following code will load it in in tiles (avoiding large memory allocations):

BitmapRegionDecoder decoder = BitmapRegionDecoder.newInstance(myStream, false);  
Bitmap region = decoder.decodeRegion(new Rect(10, 10, 50, 50), null);

See the answer here

夕嗳→ 2024-10-03 14:47:29

这是正确的方法,同时还要密切关注内存使用情况:

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
  super.onActivityResult(requestCode, resultCode, data);
  if (resultCode == RESULT_OK)
  {
    Uri imageUri = data.getData();
    Bitmap bitmap = getThumbnail(imageUri);
  }
}

public static Bitmap getThumbnail(Uri uri) throws FileNotFoundException, IOException{
  InputStream input = this.getContentResolver().openInputStream(uri);

  BitmapFactory.Options onlyBoundsOptions = new BitmapFactory.Options();
  onlyBoundsOptions.inJustDecodeBounds = true;
  onlyBoundsOptions.inDither=true;//optional
  onlyBoundsOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;//optional
  BitmapFactory.decodeStream(input, null, onlyBoundsOptions);
  input.close();

  if ((onlyBoundsOptions.outWidth == -1) || (onlyBoundsOptions.outHeight == -1)) {
    return null;
  }

  int originalSize = (onlyBoundsOptions.outHeight > onlyBoundsOptions.outWidth) ? onlyBoundsOptions.outHeight : onlyBoundsOptions.outWidth;

  double ratio = (originalSize > THUMBNAIL_SIZE) ? (originalSize / THUMBNAIL_SIZE) : 1.0;

  BitmapFactory.Options bitmapOptions = new BitmapFactory.Options();
  bitmapOptions.inSampleSize = getPowerOfTwoForSampleRatio(ratio);
  bitmapOptions.inDither = true; //optional
  bitmapOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;//
  input = this.getContentResolver().openInputStream(uri);
  Bitmap bitmap = BitmapFactory.decodeStream(input, null, bitmapOptions);
  input.close();
  return bitmap;
}

private static int getPowerOfTwoForSampleRatio(double ratio){
  int k = Integer.highestOneBit((int)Math.floor(ratio));
  if(k==0) return 1;
  else return k;
}

Mark Ingram 帖子中的 getBitmap() 调用也会调用decodeStream(),因此您不会丢失任何功能。

参考文献:

Here's the correct way of doing it, keeping tabs on memory usage as well:

protected void onActivityResult(int requestCode, int resultCode, Intent data)
{
  super.onActivityResult(requestCode, resultCode, data);
  if (resultCode == RESULT_OK)
  {
    Uri imageUri = data.getData();
    Bitmap bitmap = getThumbnail(imageUri);
  }
}

public static Bitmap getThumbnail(Uri uri) throws FileNotFoundException, IOException{
  InputStream input = this.getContentResolver().openInputStream(uri);

  BitmapFactory.Options onlyBoundsOptions = new BitmapFactory.Options();
  onlyBoundsOptions.inJustDecodeBounds = true;
  onlyBoundsOptions.inDither=true;//optional
  onlyBoundsOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;//optional
  BitmapFactory.decodeStream(input, null, onlyBoundsOptions);
  input.close();

  if ((onlyBoundsOptions.outWidth == -1) || (onlyBoundsOptions.outHeight == -1)) {
    return null;
  }

  int originalSize = (onlyBoundsOptions.outHeight > onlyBoundsOptions.outWidth) ? onlyBoundsOptions.outHeight : onlyBoundsOptions.outWidth;

  double ratio = (originalSize > THUMBNAIL_SIZE) ? (originalSize / THUMBNAIL_SIZE) : 1.0;

  BitmapFactory.Options bitmapOptions = new BitmapFactory.Options();
  bitmapOptions.inSampleSize = getPowerOfTwoForSampleRatio(ratio);
  bitmapOptions.inDither = true; //optional
  bitmapOptions.inPreferredConfig=Bitmap.Config.ARGB_8888;//
  input = this.getContentResolver().openInputStream(uri);
  Bitmap bitmap = BitmapFactory.decodeStream(input, null, bitmapOptions);
  input.close();
  return bitmap;
}

private static int getPowerOfTwoForSampleRatio(double ratio){
  int k = Integer.highestOneBit((int)Math.floor(ratio));
  if(k==0) return 1;
  else return k;
}

The getBitmap() call from Mark Ingram's post also calls the decodeStream(), so you don't lose any functionality.

References:

忆梦 2024-10-03 14:47:29

似乎 MediaStore.Images.Media.getBitmapAPI 29 中已弃用。推荐的方式是使用API 28中添加的ImageDecoder.createSource

以下是获取位图的方法:

val bitmap = if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
    ImageDecoder.decodeBitmap(ImageDecoder.createSource(requireContext().contentResolver, imageUri))
} else {
    MediaStore.Images.Media.getBitmap(requireContext().contentResolver, imageUri)
}

重要提示:ImageDecoder.decodeBitmap 读取 EXIF 方向,Media.getBitmap 不会

It seems that MediaStore.Images.Media.getBitmap was deprecated in API 29. The recommended way is to use ImageDecoder.createSource which was added in API 28.

Here's how getting the bitmap would be done:

val bitmap = if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
    ImageDecoder.decodeBitmap(ImageDecoder.createSource(requireContext().contentResolver, imageUri))
} else {
    MediaStore.Images.Media.getBitmap(requireContext().contentResolver, imageUri)
}

IMPORTANT: ImageDecoder.decodeBitmap read EXIF orientation, Media.getBitmap doesn't

噩梦成真你也成魔 2024-10-03 14:47:29
try
{
    Bitmap bitmap = MediaStore.Images.Media.getBitmap(c.getContentResolver() , Uri.parse(paths));
}
catch (Exception e) 
{
    //handle exception
}

是的,路径必须采用这样的格式

file:///mnt/sdcard/filename.jpg

try
{
    Bitmap bitmap = MediaStore.Images.Media.getBitmap(c.getContentResolver() , Uri.parse(paths));
}
catch (Exception e) 
{
    //handle exception
}

and yes path must be in a format of like this

file:///mnt/sdcard/filename.jpg

一城柳絮吹成雪 2024-10-03 14:47:29
private void uriToBitmap(Uri selectedFileUri) {
    try {
        ParcelFileDescriptor parcelFileDescriptor =
                getContentResolver().openFileDescriptor(selectedFileUri, "r");
        FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
        Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);

        parcelFileDescriptor.close();
    } catch (IOException e) {
        e.printStackTrace();
    }
}
private void uriToBitmap(Uri selectedFileUri) {
    try {
        ParcelFileDescriptor parcelFileDescriptor =
                getContentResolver().openFileDescriptor(selectedFileUri, "r");
        FileDescriptor fileDescriptor = parcelFileDescriptor.getFileDescriptor();
        Bitmap image = BitmapFactory.decodeFileDescriptor(fileDescriptor);

        parcelFileDescriptor.close();
    } catch (IOException e) {
        e.printStackTrace();
    }
}
把昨日还给我 2024-10-03 14:47:29

这是最简单的解决方案:

Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), uri);

This is the easiest solution:

Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), uri);
离去的眼神 2024-10-03 14:47:29

您可以像这样从 uri 检索位图

Bitmap bitmap = null;
try {
    bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
} catch (IOException e) {
    e.printStackTrace();
}

You can retrieve bitmap from uri like this

Bitmap bitmap = null;
try {
    bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
} catch (IOException e) {
    e.printStackTrace();
}
如此安好 2024-10-03 14:47:29
Uri imgUri = data.getData();
Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imgUri);
Uri imgUri = data.getData();
Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imgUri);
聆听风音 2024-10-03 14:47:29
Bitmap bitmap = null;
ContentResolver contentResolver = getContentResolver(); 
try {
    if(Build.VERSION.SDK_INT < 28) {
        bitmap = MediaStore.Images.Media.getBitmap(contentResolver, imageUri);
    } else {
        ImageDecoder.Source source = ImageDecoder.createSource(contentResolver, imageUri);
        bitmap = ImageDecoder.decodeBitmap(source);
    }
} catch (Exception e) {
    e.printStackTrace();
}
Bitmap bitmap = null;
ContentResolver contentResolver = getContentResolver(); 
try {
    if(Build.VERSION.SDK_INT < 28) {
        bitmap = MediaStore.Images.Media.getBitmap(contentResolver, imageUri);
    } else {
        ImageDecoder.Source source = ImageDecoder.createSource(contentResolver, imageUri);
        bitmap = ImageDecoder.decodeBitmap(source);
    }
} catch (Exception e) {
    e.printStackTrace();
}
梦醒灬来后我 2024-10-03 14:47:29
private fun setImage(view: ImageView, uri: Uri) {
        val stream = contentResolver.openInputStream(uri)
        val bitmap = BitmapFactory.decodeStream(stream)
        view.setImageBitmap(bitmap)
}
private fun setImage(view: ImageView, uri: Uri) {
        val stream = contentResolver.openInputStream(uri)
        val bitmap = BitmapFactory.decodeStream(stream)
        view.setImageBitmap(bitmap)
}
请帮我爱他 2024-10-03 14:47:29

通过使用 glide 库,您可以从 uri 获取位图,

几乎在三星设备中图像旋转时,我们必须使用 exifinterface 检查旋转,

但使用 glide 不需要检查旋转,图像总是正确接收。

在 kotlin 中,你可以获得位图,因为

CoroutineScope(Dispatchers.IO).launch {
   var bitmap = Glide.with(context).asBitmap().load(imageUri).submit().get()//this is synchronous approach                  
}

我正在使用此依赖项

api 'com.github.bumptech.glide:glide:4.12.0'
kapt 'com.github.bumptech.glide:compiler:4.12.0'

by using glide library you can get bitmap from uri,

almost in samsung devices image rotated when and we have to check rotation using exifinterface

but using glide no need to check rotation, image always correctly received.

in kotlin you can get bitmap as

CoroutineScope(Dispatchers.IO).launch {
   var bitmap = Glide.with(context).asBitmap().load(imageUri).submit().get()//this is synchronous approach                  
}

I am using this dependency

api 'com.github.bumptech.glide:glide:4.12.0'
kapt 'com.github.bumptech.glide:compiler:4.12.0'
冰雪梦之恋 2024-10-03 14:47:29

我没有看到正确的答案,所以我将这个扩展放在

fun Context.getBitmap(uri: Uri): Bitmap =
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) ImageDecoder.decodeBitmap(ImageDecoder.createSource(this.contentResolver, uri))
    else MediaStore.Images.Media.getBitmap(this.contentResolver, uri)

代码中的示例:

val bitmap = context.getBitmap(uri)

提示:您还可以更新活动/片段的扩展名,这样您就不必
根本需要写上下文。多一点合成糖)

I don't see the right answer, so I'll put this extension here

fun Context.getBitmap(uri: Uri): Bitmap =
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) ImageDecoder.decodeBitmap(ImageDecoder.createSource(this.contentResolver, uri))
    else MediaStore.Images.Media.getBitmap(this.contentResolver, uri)

Example in code:

val bitmap = context.getBitmap(uri)

Tip: You can also update the extension for activity/fragment, so you don't
need to write the context at all. A little more synth sugar)

壹場煙雨 2024-10-03 14:47:29

现在已不再使用的 getBitmap 插图我在 Kotlin 中使用以下方法

PICK_IMAGE_REQUEST ->
    data?.data?.let {
        val bitmap = BitmapFactory.decodeStream(contentResolver.openInputStream(it))
        imageView.setImageBitmap(bitmap)
    }

Inset of getBitmap which is depricated now I use the following approach in Kotlin

PICK_IMAGE_REQUEST ->
    data?.data?.let {
        val bitmap = BitmapFactory.decodeStream(contentResolver.openInputStream(it))
        imageView.setImageBitmap(bitmap)
    }
十六岁半 2024-10-03 14:47:29
  InputStream imageStream = null;
    try {
        imageStream = getContext().getContentResolver().openInputStream(uri);
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }
    final Bitmap selectedImage = BitmapFactory.decodeStream(imageStream);
  InputStream imageStream = null;
    try {
        imageStream = getContext().getContentResolver().openInputStream(uri);
    } catch (FileNotFoundException e) {
        e.printStackTrace();
    }
    final Bitmap selectedImage = BitmapFactory.decodeStream(imageStream);
吹泡泡o 2024-10-03 14:47:29
ContentResolver cr = context.getContentResolver();
try (InputStream input = cr.openInputStream(url)) {
    Bitmap bitmap = BitmapFactory.decodeStream(input);
}
ContentResolver cr = context.getContentResolver();
try (InputStream input = cr.openInputStream(url)) {
    Bitmap bitmap = BitmapFactory.decodeStream(input);
}
羁客 2024-10-03 14:47:29

使用如下 startActivityForResult 方法

        startActivityForResult(new Intent(Intent.ACTION_PICK).setType("image/*"), PICK_IMAGE);

,您可以获得如下结果:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (resultCode != RESULT_OK) {
        return;
    }
    switch (requestCode) {
        case PICK_IMAGE:
            Uri imageUri = data.getData();
            try {
                Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
            } catch (IOException e) {
                e.printStackTrace();
            }
         break;
    }
}

Use startActivityForResult metod like below

        startActivityForResult(new Intent(Intent.ACTION_PICK).setType("image/*"), PICK_IMAGE);

And you can get result like this:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (resultCode != RESULT_OK) {
        return;
    }
    switch (requestCode) {
        case PICK_IMAGE:
            Uri imageUri = data.getData();
            try {
                Bitmap bitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), imageUri);
            } catch (IOException e) {
                e.printStackTrace();
            }
         break;
    }
}
友欢 2024-10-03 14:47:29

我已经尝试了很多方法。这对我来说非常有用。

如果您从图库中选择图片。您需要注意从 intent.clipdataintent.data 获取 Uri,因为其中一个在不同版本中可能为 null。

  private fun onChoosePicture(data: Intent?):Bitmap {
        data?.let {
            var fileUri:Uri? = null

              data.clipData?.let {clip->
                  if(clip.itemCount>0){
                      fileUri = clip.getItemAt(0).uri
                  }
              }
            it.data?.let {uri->
                fileUri = uri
            }


               return MediaStore.Images.Media.getBitmap(this.contentResolver, fileUri )
}

I have try a lot of ways. this work for me perfectly.

If you choose pictrue from Gallery. You need to be ware of getting Uri from intent.clipdata or intent.data, because one of them may be null in different version.

  private fun onChoosePicture(data: Intent?):Bitmap {
        data?.let {
            var fileUri:Uri? = null

              data.clipData?.let {clip->
                  if(clip.itemCount>0){
                      fileUri = clip.getItemAt(0).uri
                  }
              }
            it.data?.let {uri->
                fileUri = uri
            }


               return MediaStore.Images.Media.getBitmap(this.contentResolver, fileUri )
}
偏爱自由 2024-10-03 14:47:29
val bitmap = context.contentResolver.openInputStream(uri).use { data ->
        BitmapFactory.decodeStream(data)
    }

您需要打开输入流

使用

它会在操作完成后自动关闭流。

val bitmap = context.contentResolver.openInputStream(uri).use { data ->
        BitmapFactory.decodeStream(data)
    }

You need to open inputstream with

use

as it will automatically close the stream after operation complete.

花辞树 2024-10-03 14:47:29

你可以做这个结构:

protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) {
    super.onActivityResult(requestCode, resultCode, imageReturnedIntent);
    switch(requestCode) {
        case 0:
            if(resultCode == RESULT_OK){
                    Uri selectedImage = imageReturnedIntent.getData();
                    Bundle extras = imageReturnedIntent.getExtras();
                    bitmap = extras.getParcelable("data");
            }
            break;
   }

通过这个你可以轻松地将 uri 转换为位图。
希望能帮助你。

you can do this structure:

protected void onActivityResult(int requestCode, int resultCode, Intent imageReturnedIntent) {
    super.onActivityResult(requestCode, resultCode, imageReturnedIntent);
    switch(requestCode) {
        case 0:
            if(resultCode == RESULT_OK){
                    Uri selectedImage = imageReturnedIntent.getData();
                    Bundle extras = imageReturnedIntent.getExtras();
                    bitmap = extras.getParcelable("data");
            }
            break;
   }

by this you can easily convert a uri to bitmap.
hope help u.

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