循环遍历 PHP 中的几个函数

发布于 2024-09-26 05:46:51 字数 420 浏览 10 评论 0原文

基本上我想实现连续执行 5-10 个函数的功能（就像通常一样）。但是，如果收到特定返回，我希望脚本返回几个步骤（例如从第 5 步回到第 3 步）并进一步继续（如 4、5、6、7、8、9、10）。示例：

<?
function_1st();
function_2nd();
function_3rd();
function_4th();
$a = function_5th();
if($a == '3') //continue from 3rd further;
function_6th();
function_7th();
?>

在本例中，它应该是 1,2,3,4,5,3,4,5,6,7,8,9,10。在此使用面向对象编程（类）会更好吗？

基本上我只需要建议，如何以正确的方式做到这一点:)

问候，乔纳斯

原文

Basically I want to achieve such functionality that 5-10 functions are executed in a row (like normally). However, I want the script to go back several steps back (ex. from 5th back to 3rd) and continue further (like 4,5,6,7,8,9,10), if specific return is received. Example:

<?
function_1st();
function_2nd();
function_3rd();
function_4th();
$a = function_5th();
if($a == '3') //continue from 3rd further;
function_6th();
function_7th();
?>

Like in this case it should be 1,2,3,4,5,3,4,5,6,7,8,9,10.
Would it be better to use object orientated programming (class) in this?

Basically I need only advice, how to make it like this in a proper waY :)

Regards,
Jonas

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万人眼中万个我 2024-10-03 05:46:51

将所有函数包装在一个开关中，如下所示：

function run($n) {
    switch($n) {
      case 1: $a = func1(); break;
      case 2: $a = func2(); break;
      case 3: $a = func3(); break;
      case 4: $a = func4(); break;
      case 5: $a = func5(); break;
      case 6: $a = func6(); break;
      case 7: $a = func7(); break;
      case 8: $a = func8(); break;
      case 9: $a = func9(); break;
      default: return $a;
    }
    run($a ? $a : $n+1);
}

wrap all the functions in a switch something like:

function run($n) {
    switch($n) {
      case 1: $a = func1(); break;
      case 2: $a = func2(); break;
      case 3: $a = func3(); break;
      case 4: $a = func4(); break;
      case 5: $a = func5(); break;
      case 6: $a = func6(); break;
      case 7: $a = func7(); break;
      case 8: $a = func8(); break;
      case 9: $a = func9(); break;
      default: return $a;
    }
    run($a ? $a : $n+1);
}

回复收藏 0 原文

何以笙箫默 2024-10-03 05:46:51

您可以将函数调用基于上一个函数返回

示例：

function one() {
   if()...
      return 'run function two';
   else 
      return 'run function four';
}

You could base the function calls on the previous function return

Example:

function one() {
   if()...
      return 'run function two';
   else 
      return 'run function four';
}

回复收藏 0 原文

亚希 2024-10-03 05:46:51

$step=1;
while($step < 99){
switch ($step){
    case 1:
        $step=function_1();
        break;
    case 2:
        $step=function_2();
        break;
    case 3:
        $step=function_3();
        break;
    ...
    case 9:
        $step=function_9();
        break;
    default:
        $step=99;
        }
    }

$step=1;
while($step < 99){
switch ($step){
    case 1:
        $step=function_1();
        break;
    case 2:
        $step=function_2();
        break;
    case 3:
        $step=function_3();
        break;
    ...
    case 9:
        $step=function_9();
        break;
    default:
        $step=99;
        }
    }

回复收藏 0 原文

夜巴黎 2024-10-03 05:46:51

使用“变量函数”或“call_user_func()函数”。我没有时间解释，请谷歌搜索关键字。

回复收藏 0 原文

油焖大侠 2024-10-03 05:46:51

为什么需要这样做？您是说，如果在调用 function_5() 之后调用 function_3() ，那么 $a 上的结果会有所不同，然后它将通过 function_5() 的检查？

您可能需要重新思考您的总体逻辑。

顺便说一句，不要使用短标签。写出

<?php

Why would you need to do this? Are you saying that the results on $a will be different if function_3() is called on it after function_5() has been called on it and then it will pass the check on function_5() ?

You may need to rethink your logic in general.

By the way, don't use short tags. Write out