Silverlight Http Post 上传图片
我一直在尝试执行 HTTP Post 请求,以在 Windows Phone 7 应用程序的 silverlight 应用程序中上传图像。在线示例代码没有让我从 API 获得所需的响应。谁能提供一个可以执行此操作的工作代码吗?
我所说的期望响应是指 API 响应说上传的文件格式无法读取。
提前致谢!
这是我的代码:
private void post_image(version, username,password,job-id, serviceUri)
{
if (session_free.bLoggedIn)
{
bool submit_success = false;
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(new Uri(serviceUri));
IsolatedStorageFileStream stream = IsolatedStorageFile.GetUserStoreForApplication().OpenFile("file.jpg", FileMode.Open);
request.PostMultiPartAsync(new Dictionary<string, object> { { "version", version }, { "username", user }, { "password", pass }, { filename, stream } }, new AsyncCallback(asyncResult =>
{
Thread.Sleep(1000);
HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(asyncResult);
Stream responseStream = response.GetResponseStream();
StreamReader reader = new StreamReader(responseStream);
Post_Result = reader.ReadToEnd();
this.Dispatcher.BeginInvoke(delegate
{
MessageBox.Show(Post_Result);
response.Close();
});
}), filename);
Thread.Sleep(1000);
}
else
{
MessageBox.Show("User not signed in! Please login to continue...", "Invalid Authentication", MessageBoxButton.OK);
}
}
public class DataContractMultiPartSerializer
{
private string boundary;
public DataContractMultiPartSerializer(string boundary)
{
this.boundary = boundary;
}
private void WriteEntry(StreamWriter writer, string key, object value, string filename)
{
if (value != null)
{
writer.Write("--");
writer.WriteLine(boundary);
if (value is IsolatedStorageFileStream)
{
IsolatedStorageFileStream f = value as IsolatedStorageFileStream;
writer.WriteLine(@"Content-Disposition: form-data; name=""{0}""; filename=""{1}""", key, filename);
writer.WriteLine("Content-Type: image/jpeg");
writer.WriteLine("Content-Length: " + f.Length);
writer.WriteLine();
writer.Flush();
Stream output = writer.BaseStream;
Stream input = f;
byte[] buffer = new byte[4096];
for (int size = input.Read(buffer, 0, buffer.Length); size > 0; size = input.Read(buffer, 0, buffer.Length))
{
output.Write(buffer, 0, size);
}
output.Flush();
writer.WriteLine();
}
else
{
writer.WriteLine(@"Content-Disposition: form-data; name=""{0}""", key);
writer.WriteLine();
writer.WriteLine(value.ToString());
}
}
}
public void WriteObject(Stream stream, object data, string filename)
{
StreamWriter writer = new StreamWriter(stream);
if (data != null)
{
if (data is Dictionary<string, object>)
{
foreach (var entry in data as Dictionary<string, object>)
{
WriteEntry(writer, entry.Key, entry.Value, filename);
}
}
else
{
foreach (var prop in data.GetType().GetFields())
{
foreach (var attribute in prop.GetCustomAttributes(true))
{
if (attribute is System.Runtime.Serialization.DataMemberAttribute)
{
DataMemberAttribute member = attribute as DataMemberAttribute;
writer.Write("{0}={1}&", member.Name ?? prop.Name, prop.GetValue(data));
}
}
}
}
writer.Flush();
}
}
}
I have been trying to perform an HTTP Post request to upload an image in a silverlight application for a windows phone 7 application. The sample codes online do not get me the desired response from the API. Could anyone please provide a working code which does this?
By desired response I mean that the API responds saying that the uploaded file is in a format which cannot be read.
Thanks in advance!
Here is my code:
private void post_image(version, username,password,job-id, serviceUri)
{
if (session_free.bLoggedIn)
{
bool submit_success = false;
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(new Uri(serviceUri));
IsolatedStorageFileStream stream = IsolatedStorageFile.GetUserStoreForApplication().OpenFile("file.jpg", FileMode.Open);
request.PostMultiPartAsync(new Dictionary<string, object> { { "version", version }, { "username", user }, { "password", pass }, { filename, stream } }, new AsyncCallback(asyncResult =>
{
Thread.Sleep(1000);
HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(asyncResult);
Stream responseStream = response.GetResponseStream();
StreamReader reader = new StreamReader(responseStream);
Post_Result = reader.ReadToEnd();
this.Dispatcher.BeginInvoke(delegate
{
MessageBox.Show(Post_Result);
response.Close();
});
}), filename);
Thread.Sleep(1000);
}
else
{
MessageBox.Show("User not signed in! Please login to continue...", "Invalid Authentication", MessageBoxButton.OK);
}
}
public class DataContractMultiPartSerializer
{
private string boundary;
public DataContractMultiPartSerializer(string boundary)
{
this.boundary = boundary;
}
private void WriteEntry(StreamWriter writer, string key, object value, string filename)
{
if (value != null)
{
writer.Write("--");
writer.WriteLine(boundary);
if (value is IsolatedStorageFileStream)
{
IsolatedStorageFileStream f = value as IsolatedStorageFileStream;
writer.WriteLine(@"Content-Disposition: form-data; name=""{0}""; filename=""{1}""", key, filename);
writer.WriteLine("Content-Type: image/jpeg");
writer.WriteLine("Content-Length: " + f.Length);
writer.WriteLine();
writer.Flush();
Stream output = writer.BaseStream;
Stream input = f;
byte[] buffer = new byte[4096];
for (int size = input.Read(buffer, 0, buffer.Length); size > 0; size = input.Read(buffer, 0, buffer.Length))
{
output.Write(buffer, 0, size);
}
output.Flush();
writer.WriteLine();
}
else
{
writer.WriteLine(@"Content-Disposition: form-data; name=""{0}""", key);
writer.WriteLine();
writer.WriteLine(value.ToString());
}
}
}
public void WriteObject(Stream stream, object data, string filename)
{
StreamWriter writer = new StreamWriter(stream);
if (data != null)
{
if (data is Dictionary<string, object>)
{
foreach (var entry in data as Dictionary<string, object>)
{
WriteEntry(writer, entry.Key, entry.Value, filename);
}
}
else
{
foreach (var prop in data.GetType().GetFields())
{
foreach (var attribute in prop.GetCustomAttributes(true))
{
if (attribute is System.Runtime.Serialization.DataMemberAttribute)
{
DataMemberAttribute member = attribute as DataMemberAttribute;
writer.Write("{0}={1}&", member.Name ?? prop.Name, prop.GetValue(data));
}
}
}
}
writer.Flush();
}
}
}
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评论(1)
您使用多部分消息有什么原因吗?
您使用的
PostMultiPartAsync
方法是什么?大概它是来自某个地方的扩展方法?将来,尝试提供最小的、完整的代码来演示该问题。
无论如何,抱歉,这不是一个完整的工作示例,但以下是一种方法的步骤。
创建请求并为
BeginGetRequestStream
设置回调在该回调中,获取请求流并向其中写入数据。
设置服务器响应的回调。
检查服务器上的一切是否正常
在服务器上,您需要反序列化数据并将其转换回适当的图像。
HTH。
Is there a reason you're using a multipart message?
What is the
PostMultiPartAsync
method you're using? Presumably it's an extension method from somewhere?In future, try and provide the smallest, complete, piece of code which demonstrates the issue.
Anyway, sorry it's not a full working example, but here are the steps for one way to do this.
Create request and set a calback for
BeginGetRequestStream
In that callback, get the request stream and write your data to it.
Set a callback for the response from the server.
Check that everything worked OK on the server
On the server you will need to deserialize the data and turn it back into an image as appropriate.
HTH.