如何在 Makefile 中获取 make 命令的 pid？

发布于 2024-09-25 18:29:06 字数 271 浏览 11 评论 0原文

我想使用此构建特有的临时目录。如何在 Makefile 中获取 make 命令的 pid？

我尝试过：

TEMPDIR = /tmp/myprog.$$$$

但这似乎将 TEMPDIR 存储为 /tmp/myprog.$$ ，然后将 eval 作为引用此的每个命令的新 pid ！我如何获得所有这些的一个pid（我更喜欢make pid，但任何独特的东西都可以）。

提前致谢。

原文

I want to use a temp directory that will be unique to this build. How can I get the pid of my make command in the Makefile?

I tried:

TEMPDIR = /tmp/myprog.$$

but this seems to store TEMPDIR as /tmp/myprog.$$ and then eval as a new pid for every command which refs this! How do I get one pid for all of them (I'd prefer the make pid, but anything unique will do).

Thanks in advance.

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谢绝鈎搭 2024-10-02 18:29:06

尝试使用 mktemp 创建唯一的临时文件名。 -d 选项将创建一个目录而不是文件。

TEMPFILE := $(shell mktemp)
TEMPDIR := $(shell mktemp -d)

注意冒号。（编者注：这会导致 make 对函数求值一次并为其赋值，而不是为每个对 $(TEMPDIR) 的引用重新求表达式。）

Try mktemp for creating unique temporary filenames. The -d option will create a directory instead of a file.

TEMPFILE := $(shell mktemp)
TEMPDIR := $(shell mktemp -d)

Note the colon. (Editor's note: This causes make to evaluate the function once and assign its value instead of re-evaluating the expression for every reference to $(TEMPDIR).)

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半边脸i 2024-10-02 18:29:06

make 为它启动的每个命令启动一个新的 shell。使用 bash（未检查其他 shell）echo $PPID 给出父进程 ID（即 make）。

all: subtarget 
        echo $PPID
        echo $(shell echo $PPID)

subtarget:
        echo $PPID

make starts a new shell for each command it starts. Using bash (didn't check for other shells) echo $PPID gives the parent process ID (which is make).

all: subtarget 
        echo $PPID
        echo $(shell echo $PPID)

subtarget:
        echo $PPID

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喜爱纠缠 2024-10-02 18:29:06

TEMPDIR := $(shell mktemp)

问题是：每次运行 make 时，它都会创建一个临时文件。无论您是否使用它，也无论您使用的 make 目标如何。这意味着：要么您在每个目标中删除该文件，要么它们随时都不会被删除。

我更喜欢添加 -u 参数：

TEMPDIR := $(shell mktemp -u)

这使得 mktemp 创建唯一的文件名而不创建文件。现在您可以在需要的目标中创建文件。当然，有可能出现竞争条件，即文件在创建之前已被另一个进程使用。这不太可能，但是不要在提升的命令中使用它，例如make install。

TEMPDIR := $(shell mktemp)

The problem is: every time you run make, it will create a temporary file. Regardless of you use it or not and regardless of the make target you use. That means: either you delete this file in every target or you they will not be deleted anytime.

I prefer to add the -u parameter:

TEMPDIR := $(shell mktemp -u)

This makes mktemp to create an unique filename without creating the file. Now you can create the file in the targets you need them. Of course there is a chance of a race conditions, where the file is used by another process before you create it. That is very unlikely, but do not use it in an elevated command, like make install.

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小红帽 2024-10-02 18:29:06

这是您问题的答案，似乎没有人愿意给您：

TEMPDIR := /tmp/myprog.$(shell ps -o ppid $$)

当然，这不能保证是唯一的。

Here is the answer to your question, which nobody seemed to want to give you:

TEMPDIR := /tmp/myprog.$(shell ps -o ppid $$)

Of course, this is not guaranteed to be unique.

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别念他 2024-10-02 18:29:06

您可以使用日期字符串。除非您同时启动多个构建，否则这应该非常接近。

类似于以下

pid_standin := $(shell date +%Y-%m-%d_%H-%M-%S)

file: 
    echo $(pid_standin)

$ Make
2010-10-04_21-01-58

更新：如评论中所述，如果您使用 name = val 语法设置变量，则它是每次使用时都会重新评估。 := 语法设置它并且不重新评估该值，尽管使用反引号 `` 似乎可以以某种方式解决这个问题。您确实想使用 $(shell CMD) 构造来完成这样的事情。

You could use a date string. Unless you're kicking off multiple builds at the same time this should be pretty close.

Something like the following

pid_standin := $(shell date +%Y-%m-%d_%H-%M-%S)

file: 
    echo $(pid_standin)

$ Make
2010-10-04_21-01-58

Update: As noted in the comment if you set a variable with name = val syntax it is re-evaluated each time it's used. The := syntax sets it and doesn't re-evaluate the value, though using back-ticks `` seems to get around this somehow. You really want to use the $(shell CMD) construct for stuff like this.

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