NSPredicate、NsNumber numberWithFloat:0.0 (iPhone)

发布于 2024-09-25 14:13:23 字数 338 浏览 2 评论 0原文

您好，我有带有数字属性的核心数据数据库。它们是 NSNumber。默认值是 0.0，但是当我尝试执行一些 NSPredicated 获取时，我得到“'NSInvalidArgumentException'，原因：'无效谓词：nil RHS'”只是因为属性值为 0.0

创建谓词：

[NSPredicate predicateWithFormat:@"(startValue => %@) AND (endValue <= %@) AND (someId == %@)",startNSNumber,endNSNumber, idString]

我该如何解决这个问题？

原文

hi i have Core Data database with numerical attributes. they are NSNumbers. Default value is 0.0 but when i try to do some NSPredicated fetch, i get "'NSInvalidArgumentException', reason: 'Invalid predicate: nil RHS'" just because attribute value is 0.0

The predicate is created with:

[NSPredicate predicateWithFormat:@"(startValue => %@) AND (endValue <= %@) AND (someId == %@)",startNSNumber,endNSNumber, idString]

how can i solve this problem ?

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昔日梦未散 2024-10-02 14:13:23

您将浮标添加为对象，而不是浮标？试试这个：

[NSPredicate predicateWithFormat:@"(startValue => %f) AND (endValue <= %f) AND (someId == %@)",startNSNumber,endNSNumber, idString];

You're adding the floats as objects, not as floats? Try this :

[NSPredicate predicateWithFormat:@"(startValue => %f) AND (endValue <= %f) AND (someId == %@)",startNSNumber,endNSNumber, idString];

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撩发小公举 2024-10-02 14:13:23

我坚信您的变量之一为零或已自动释放...

尝试以下操作：

NSNumber *num1 = [NSNumber numberWithFloat:2.0];
NSNumber *num2 = [NSNumber numberWithFloat:3.0];
NSString *str = @"Test";
[NSPredicate predicateWithFormat:@"(startValue => %@) AND (endValue <= %@) AND (someId == %@)", num1, num2, str];

如果成功，则问题出在您的变量上。

如果您希望有时 num1 或 num2 为 nil，那么您可以将谓词重写为：

[NSPredicate predicateWithFormat:@"(startValue => %@) AND (endValue <= %@) AND (someId == %@)", num1 ? num1 : [NSNumber numberWithFloat:0.0], num2 ? num2 : [NSNumber numberWithFloat:0.0], idString];

I strongly believe one of your variables is nil or was autoreleased...

try this:

NSNumber *num1 = [NSNumber numberWithFloat:2.0];
NSNumber *num2 = [NSNumber numberWithFloat:3.0];
NSString *str = @"Test";
[NSPredicate predicateWithFormat:@"(startValue => %@) AND (endValue <= %@) AND (someId == %@)", num1, num2, str];

If this succeeds that the problem is with your variables.

If you expect either num1 or num2 to be nil sometimes, then you could rewrite the predicate as:

[NSPredicate predicateWithFormat:@"(startValue => %@) AND (endValue <= %@) AND (someId == %@)", num1 ? num1 : [NSNumber numberWithFloat:0.0], num2 ? num2 : [NSNumber numberWithFloat:0.0], idString];

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梦初启 2024-10-02 14:13:23

好吧，鉴于您提供的谓词，简单的答案是：

startNSNumber、endNSNumber 或 idString 为 nil。如果您想将 NSPredicate 中的某些内容与 nil 进行比较，则需要替换为 [NSNull null]，而不是 nil代码>.

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感情废物 2024-10-02 14:13:23

IN NSpredicate 使用字符串值作为 float 字典 key.floatValue 并轻松使用。

[NSPredicate predicateWithFormat:@"(startValue.floatValue => %f) AND (endValue.floatValue <= %f) AND (someId == %@)",startNSNumber,endNSNumber, idString]

我认为这篇文章很有用。

IN NSpredicate use string value as float the Dictionary key.floatValue and easily use.

[NSPredicate predicateWithFormat:@"(startValue.floatValue => %f) AND (endValue.floatValue <= %f) AND (someId == %@)",startNSNumber,endNSNumber, idString]

I thing this post useful.

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