如何显示通过套接字接收到的字符？

发布于 2024-09-25 03:50:41 字数 473 浏览 8 评论 0原文

我有一个非常简单的 Ruby 程序，充当“回显服务器”。当您通过 telnet 连接到它时，您输入的任何文本都会回显。那部分正在工作。如果我添加“putc”语句来在运行程序的控制台上打印每个接收到的字符，则仅打印显示的第一个字符。之后，它继续将信息回显给 telnet 客户端，但控制台上没有打印任何内容。

以下是一个显示该问题的小型精简程序。

我对 Ruby 非常陌生，可能犯了一个典型的菜鸟错误。我做错了什么？

require 'socket'  

puts "Simple Echo Server V1.0"  
server = TCPServer.new('127.0.0.1', '2150')  
cbuf = ""  

while socket = server.accept  
    cbuf = socket.readchar  
    socket.putc cbuf  
    putc cbuf  
end

原文

I have a very simple Ruby program that acts as an "echo server". When you connect to it via telnet any text you type is echoed back. That part is working. If I add a 'putc' statement to also print each received character on the console running the program only the very first character displayed is printed. After that it continues to echo things back to the telnet client but there is nothing printed on the console.

The following is a small, stripped down program that exhibits the problem.

I am very new to Ruby and have probably made a typical rookie mistake. What did I do wrong?

require 'socket'  

puts "Simple Echo Server V1.0"  
server = TCPServer.new('127.0.0.1', '2150')  
cbuf = ""  

while socket = server.accept  
    cbuf = socket.readchar  
    socket.putc cbuf  
    putc cbuf  
end

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为你拒绝所有暧昧 2024-10-02 03:50:41

问题是您的代码仅在每次有人连接时运行一次 while 循环（TCPServer#accept 接受连接）。尝试更多类似的东西：

require 'socket'  

puts "Simple Echo Server V1.0"  
server = TCPServer.new('127.0.0.1', '2150')

socket = server.accept  

while line = socket.readline
  socket.puts line
  puts line
end

The problem is that your code is only running the while loop once for every time somebody connects (TCPServer#accept accepts a connection). Try something more like:

require 'socket'  

puts "Simple Echo Server V1.0"  
server = TCPServer.new('127.0.0.1', '2150')

socket = server.accept  

while line = socket.readline
  socket.puts line
  puts line
end

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