如何处理JPA多对一关系？

Question

我正在设计一个用于收集天气数据的应用程序。我有 2 个 POJO 对象“位置”和“记录”。 Location包含有关经纬度和当前天气状况的信息，Record包含特定位置一段时间内的所有天气信息，因此与Location具有多对一关系。我的类的定义如下：

Location.java

@Entity
@Table(name = "location")
@NamedQueries( {
 @NamedQuery(name = "findLocations", query = "SELECT e FROM Location e ORDER BY e.longitude, e.latitude"),
 @NamedQuery(name = "findLocationByLatLong", query = "SELECT e from Location e WHERE e.latitude = :latitude AND e.longitude = :longitude"),
 @NamedQuery(name = "findLocationById", query = "SELECT e from Location e WHERE e.id = :id"),
 @NamedQuery(name = "deleteLocationById", query= "DELETE Location e WHERE e.id = :id"),
 @NamedQuery(name = "updateLocation", query = "UPDATE Location e SET e.lastModifiedDate = :lastModifiedDate WHERE e.id = :id")})

public class Location implements Serializable {

 /**
  * 
  */
 private static final long serialVersionUID = 1L;

 @Id
 @GeneratedValue(strategy = GenerationType.AUTO)
 protected Long id;

 @Column(name="latitude", nullable=false)
 protected String latitude;

 @Column(name="longitude", nullable=false)
 protected String longitude;

 @Column(name="lastModifiedDate")
 @Temporal(TemporalType.TIMESTAMP)
 private Date lastModifiedDate;

 @Column(name="windDirection")
 private float windDirection;

 @Column(name="windSpeed")
 private float windSpeed;

 @Column(name="temperature")
 private float temperature;
}

和 Record.java

@Entity
@Table(name = "weatherdata")
@NamedQueries( {
  @NamedQuery(name = "findWeatherRecordById", query = "SELECT e from Record e WHERE e.id = :id"),
  @NamedQuery(name = "findWeatherRecords", query = "SELECT e from Record e WHERE e.parent = :parent") })
public class Record implements Serializable{

 /**
  * 
  */
 private static final long serialVersionUID = 1L;

 @Id
 @GeneratedValue(strategy = GenerationType.AUTO)
 @Column(name="id")
 protected Long id;

 @Column(name="mTime")
 @Temporal(TemporalType.TIMESTAMP)
 private Date mtime;

 @Column(name="windDirection")
 private float windDirection;

 @Column(name="windSpeed")
 private float windSpeed;

 @Column(name="temperature")
 private float temperature;

 @ManyToOne(cascade = { CascadeType.ALL }, targetEntity=Location.class, fetch = FetchType.EAGER)
 @JoinColumn(name="locationId")
 protected Location parent;
}

我传入的数据采用以下形式：

latitude,longitude,date,winddirection,windspeed,temperature
36.9822,-122.0153,20100907000000.00,158,2.68,20.57
38.1838,-120.54,20100907000000.00,248,0,26.68
38.3495,-121.9688,20100907000000.00,149,0.45,33.9
38.41935,-121.36029,20100907000000.00,322,0.9,33.9
37.91617,-122.286,20100907000000.00,224,0,24.46
38.587,-121.3162,20100907000000.00,315,0,34.46
36.8717,-121.6555,20100907000000.00,294,3.13,18.34

现在，每当我获得一条记录时，我想将其插入到 Record 表中。由于我有 Location 的外键，因此我还将添加 Location 表的 locationId。 另一件事是，位置表没有预先填充。因此，每当有新记录出现时，我首先将其插入位置表中，然后使用外键填充记录表。我不想在位置表中出现重复的位置条目。如您所见，位置表还将包含最新的温度、风速和风向数据。

我正在使用以下代码来完成此操作：

Location loc = handler.getLocation(line);   
//loc.setTemperature(0);

Location dbLoc = null;

try {
    Query q = eManager.createNamedQuery("findLocationByLatLong");
    q.setParameter("latitude", loc.getLatitude());
    q.setParameter("longitude", loc.getLongitude());
    dbLoc = (Location) q.getSingleResult();                     
} catch (Exception e) {
    System.out.println("Location not found! Creating new location");
    Logger.getLogger("WeatherRecorderBean.class").log(Level.WARNING, e.getMessage());
}


Record r = handler.getRecord(line);

if(dbLoc!=null) {
    r.setParent(dbLoc);

    dbLoc.setLastModifiedDate(r.getMtime());//I am doing this so as to know what time the weather change entry is about
    dbLoc.setWindDirection(r.getWindDirection());
    dbLoc.setWindSpeed(r.getWindSpeed());
    dbLoc.setTemperature(r.getTemperature());

    eManager.merge(r);                      
}
else {
    dbLoc = new Location();
    dbLoc.setLatitude(loc.getLatitude());
    dbLoc.setLongitude(loc.getLongitude());
    //eManager.persist(dbLoc);

    r.setParent(dbLoc);                     

    dbLoc.setLastModifiedDate(r.getMtime());
    dbLoc.setWindDirection(r.getWindDirection());
    dbLoc.setWindSpeed(r.getWindSpeed());
    dbLoc.setTemperature(r.getTemperature());

    eManager.merge(r);
    //eManager.merge(dbLoc);

}

但是通过这样做，发生的情况是位置被重复。这意味着我在位置表中有多个相同经度和纬度但具有不同温度、风速数据的条目。我想要完成的是一个纬度和经度的单个条目，并使用最新数据更新风速、温度和风向字段。

请帮忙！

Answer 1

您将记录中的ALL操作级联到位置，因此当您合并新的记录时和< /strong> 其新的父 Location，无需再次合并瞬态 Location（否则您将得到重复的行）。

我在下面的代码中添加了一些注释（我没有修复所有问题，IMO 还有更多问题，但建议的更改应该至少删除重复 Location 条目的创建）：

if(dbLoc==null) {
  dbLoc = new Location();
  dbLoc.setLatitude(loc.getLatitude());
  dbLoc.setLongitude(loc.getLongitude());
  r.setParent(dbLoc);

  // add changes on the dbLoc here

  eManager.merge(r);  // here you're merging r and the dbLoc 

  //loc.setLastModifiedDate(r.getMtime()); // why are you modifying the line from the file?
  //loc.setWindDirection(r.getWindDirection());
  //loc.setWindSpeed(r.getWindSpeed());
  //loc.setTemperature(r.getTemperature());
  //eManager.persist(loc);    
  //System.out.println("Location id : "+loc.getId());

  //eManager.merge(dbLoc); // here you're merging a transient dbLoc again

}

Answer 2

已解决:-)

public Location saveLocation(Location loc) {
    eManager.clear();
    eManager.setFlushMode(FlushModeType.COMMIT);
    //eManager.setFlushMode(FlushModeType.COMMIT);
    Query q = eManager.createNamedQuery("findLocationByLatLong");
    q.setParameter("latitude", loc.getLatitude());
    q.setParameter("longitude", loc.getLongitude());
    try {
        Location dummy = (Location) q.getSingleResult();
        eManager.clear();
        // eManager.flush();
        return dummy;
    } catch (NoResultException ex) {
        Logger.getLogger("WeatherRecorderBean.class").log(Level.WARNING,
                ex.getMessage());
        eManager.clear();
        eManager.merge(loc);
        eManager.flush();
        return loc;
    } catch (Exception ex) {
        Logger.getLogger("WeatherRecorderBean.class").log(Level.WARNING, "Should never get here! "+ex.getMessage());
        return null;
    }
}

我创建了一个用于保存位置的新函数。
我也遇到了一些同步问题。我在 MDB onMessage() 函数中有这个函数。因此，在一个 onMessage() 完成之前，另一个 onMessage() 已开始，因此会创建重复的条目！

希望这对将来的人有帮助！