嵌套函数调用
这已经让我彻底抓狂了。我有一个像这样的替代函数：
(define (mysub x bind body) ;; x, bind, body are lists
...)
我需要这样调用该函数：
;;this is the explicit call for when length x = length bind = 2.
;;how do I generalize these nested calls?
;;in case it's not obvious, i'm passing mysub as the third parameter
;;to a previous mysub call
(mysub (first x) (first bind) (mysub (first (rest x)) (first (rest bind)) body)
这只是我作业的一小部分。
我尝试过使用带有 lambda 函数的映射，但我尝试过的每一种方法都会给我带来类似的结果：
( (x1)(bind1)(body) (x2)(bind2)(body) ) ;;I've found a million ways to get this
我需要调用它，直到 x 列表为空。 我不知道为什么这个想法让我如此困惑，非常感谢任何帮助。
This has been driving me absolutely nuts. I have a substitute function like this:
(define (mysub x bind body) ;; x, bind, body are lists
...)
I need to call the function like this:
;;this is the explicit call for when length x = length bind = 2.
;;how do I generalize these nested calls?
;;in case it's not obvious, i'm passing mysub as the third parameter
;;to a previous mysub call
(mysub (first x) (first bind) (mysub (first (rest x)) (first (rest bind)) body)
This is only small part of my homework.
I've tried using a map with lambda functions, but every approach I've tried leaves me with something like:
( (x1)(bind1)(body) (x2)(bind2)(body) ) ;;I've found a million ways to get this
I need to call this until the x list is empty.
I don't know why this idea is tripping me up so much, any help is greatly appreciated.
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（1）
从 length=2 的示例来看，我认为概括类似于
(foldr mysub body x bind)，它将mysub应用于x 中的每对值和绑定。使用
map在这里不起作用，因为您需要通过每个mysub调用传递body的“当前”值。From the example with length=2, I think the generalization is something like
(foldr mysub body x bind), which appliesmysubto each pair of values inxandbind.Using
mapdoesn't work here, because you need to pass around the "current" value ofbodythrough eachmysubcall.