Linux：如何检测进程是如何启动的
我的程序如何检测它是如何启动的：由某人使用命令行启动还是由另一个进程启动？
该程序有一个可选的交互部分，当它由另一个进程启动时我想禁止它 - 在后台运行；但是当它从终端启动时，我希望它执行交互操作。
[编辑] 是否可以通过 C++ 程序执行。
How can my program detect how it was started: by someone using the command-line or by another process?
The program has an optional interactive part that I want to suppress when it was started by another process - running in the background; but when it was started from a terminal I want it to do the interactive bit.
[edit] If it is possible to do from a C++ program.
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检查您的标准输入是否
isatty，例如Check if your stdin
isatty, eg通常，只需提供调用者可用于在非交互模式下运行的命令行参数。你可以做更奇特的事情，但这很常见——很多时候，它 -q 表示安静。
Usually, just provide command-line arguments that the caller can use to run in non-interactive mode. You can do fancier things, but that's pretty common -- a lot of times, it -q for quiet.
Bash 有一个简单的测试，可以告诉您脚本是否是从 TTY 启动的：
Bash has a simple test that will tell you if the script was started from a TTY:
<unistd.h> defines the isatty function that you could use to check if the input (0) or output (1) file descriptors are connected to a terminal (which means it is an interactive session).