在 MDI 中从另一个子窗口打开子窗口

发布于 2024-09-24 19:45:54 字数 996 浏览 0 评论 0原文

我在使用 Windows 窗体开发 MDI 应用程序期间遇到一些问题。

想象一下具有 3 个表单的小型测试应用程序：Form1、Form2 和 Form3。 Form1 是一个 MdiContainer（带有带有单个按钮的附加 menuStrip 元素 - 用于测试目的）。 Form2 仅包含单个按钮。单击 Form1 菜单条按钮即可打开 Form2。 Form3 应通过单击 Form2 按钮打开。

我已经使用谷歌解决了这个问题，但没有任何帮助。

我的代码如下：

Form1

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void menu2ToolStripMenuItem_Click(object sender, EventArgs e)
    {
        Form2 chWin = new Form2();
        chWin.MdiParent = this;
        chWin.Show();
    }
}

Form2

public partial class Form2 : Form
{
    public Form2()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        Form3 form3 = new Form3();
        form3.Show();
    }
}

Form3 实际上根本没有代码。

很明显，我已经以某种方式声明 Form3 应该是 Form1 子级，但是如何声明呢？：）

提前致谢！

原文

I have some problems during MDI application development using Windows Forms.

Imagine small test application with 3 forms: Form1, Form2 and Form3.
Form1 is an MdiContainer (with attached menuStrip element with single botton - for test purposes).
Form2 contains only single button. Form2 openes by the click on Form1 menuStrip button.
Form3 should open by Form2 button click.

I've already used google for this trouble, but nothing helpful.

My code is below:

Form1

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    private void menu2ToolStripMenuItem_Click(object sender, EventArgs e)
    {
        Form2 chWin = new Form2();
        chWin.MdiParent = this;
        chWin.Show();
    }
}

Form2

public partial class Form2 : Form
{
    public Form2()
    {
        InitializeComponent();
    }

    private void button1_Click(object sender, EventArgs e)
    {
        Form3 form3 = new Form3();
        form3.Show();
    }
}

Form3 actually has no code at all.

It is quite obvious that I have somehow declare that Form3 should be Form1 child but how? :)

Thanks in advance!

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