在 Javascript 中检查电子邮件地址

发布于 2024-09-24 18:09:59 字数 761 浏览 2 评论 0原文

我想很多人以前都做过一些类似的开发任务：

我想检查人们的电子邮件地址是否只匹配@tomtom.com或@stream.com。

目前，我想到了两个解决方案：

使用 indexof() 函数

var checkTomTomEmail=eo.data.username.indexOf("@tomtom.com");
var checkStreamEmail=eo.data.username.indexOf("@stream.com");


if (checkTomTomEmail > 0 || checkStreamEmail > 0 )
{
    //运行登录代码
}


别的 
{
    //请使用您的tomtom或stream电子邮件登录 
}

使用match

var patt1=/@tomtom.com/gi;
var patt2=/@stream.com/gi;
var checkTomTomEmail=eo.data.username.match(patt1);
var checkStreamEmail=eo.data.username.match(patt2);


if(indexOf(checkTomTomEmail)> 1 ||indexOf (checkStreamEmail)>1)
{
    //登录 
}

我仍然认为我还没有考虑所有细节。有什么建议吗？
谢谢

原文

I think many people have done some similar development tasks before:

I would like to check the people's email address whether only match @tomtom.com or @stream.com.

Currently, I have two solutions in my mind:

Using indexof() function

var checkTomTomEmail=eo.data.username.indexOf("@tomtom.com");
var checkStreamEmail=eo.data.username.indexOf("@stream.com");


if (checkTomTomEmail >0 || checkStreamEmail >0 )
{
    //Run the login code
}


Else 
{
    //Please login with your tomtom or stream email 
}

Using match

var patt1=/@tomtom.com/gi;
var patt2=/@stream.com/gi;
var checkTomTomEmail=eo.data.username.match(patt1);
var checkStreamEmail=eo.data.username.match(patt2);


if(indexOf(checkTomTomEmail)> 1 ||indexOf (checkStreamEmail)>1)
{
    //Login 
}

I still think I do not consider all the detail yet. Any suggestions?
Thanks

分享到QQ

分享到微博

如果你对这篇内容有疑问，欢迎到本站社区发帖提问参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。

发布评论

需要登录才能够评论，你可以免费注册一个本站的账号。

单调的奢华 2024-10-01 18:09:59

也许，如果人们只允许输入这两个地址的电子邮件，您应该只收集用户名，然后允许他们使用单选按钮选择@tomtom.com 或@stream.com。

如果您仍然想走 javascript 路线，那么您的正则表达式可以合并到单个语句中

var emailPatt=/@(tomtom|stream).com/gi;

if(emailPatt.test(eo.data.username))
{
    //Login 
}

Perhaps if people are only allowed to enter emails for those two addresses you should only collect the username and then allow them to choose @tomtom.com or @stream.com using radiobuttons.

If you still want to go the javascript route then your regex can be combined into a single statement

var emailPatt=/@(tomtom|stream).com/gi;

if(emailPatt.test(eo.data.username))
{
    //Login 
}

回复收藏 0 原文

只是偏爱你 2024-10-01 18:09:59

这样怎么样...

var emailRegex = /^([0-9a-z])+@(tomtom|stream)\.com$/ig;
if (emailRegex.test(emailRegex)) {
    // Login
}

我们可以执行 .test(...) 来查看是否有匹配项，而不是执行 .match(...) - 您将得到一个字符串。

此模式保证以下几点：

电子邮件地址的“用户名”部分必须至少包含一个字符（例如，[电子邮件受保护])
用户名必须由数字或字母组成（大写/小写 - 无关紧要，因为末尾有 /i）
输入必须包含整个电子邮件地址没有前导或尾部空格。例如，“ [email protected] ”将会失败，它只会接受“[电子邮件受保护]”。）

您可以通过以下方式进一步自定义：也就是说，确保用户名必须至少有 3 个字符，您可以在电子邮件地址中使用下划线或破折号等。

要回答您的问题，这两种解决方案都不起作用。原因：

用户可以输入“[email protected] Hello”，然后就可以了将通过您的验证。
特别是在解决方案 #2 中，点“.”是正则表达式保留的字符，这意味着它将匹配任何内容，因此，如果用户输入“@tomtom1com”，它将通过...

有关正则表达式的更多信息：http://www.regular-expressions.info/reference.html

How about this...

var emailRegex = /^([0-9a-z])+@(tomtom|stream)\.com$/ig;
if (emailRegex.test(emailRegex)) {
    // Login
}

Instead of performing a .match(...) - Which you'll get a string back, we can perform a .test(...) to see if anything matches.

This pattern guarantees the following:

The "username" part of the email address must at least have a SINGLE character (For example, [email protected])
Username must be composed of a digit or an alphabet (Upper/Lower case - Doesn't matter because of the /i at the end)
Input must contain the entire email address without leading or tailing spaces. For example, " [email protected] " will fail, it'll only accept "[email protected]".)

You can customize this further by, saying, making sure username must have at least 3 characters, you can use underscore or dashes in the email address, etc.

To answer your question, both solutions won't work. Reasons:

User can enter "[email protected] Hello", and it'll pass both of your validation.
Specifically on solution #2, the dot '.' is a Regex-reserved character, it means it'll match anything, so, if the user enters " @tomtom1com", it'll pass...

More on Regex: http://www.regular-expressions.info/reference.html

回复收藏 0 原文

~没有更多了~