用于显示 sqlite 表中图像的 NSURL 代码
我正在使用此 NSURL 代码来显示图像。我想要做的是插入数据库表中的 url 来代替下面代码中显示的静态 url：
有谁知道我应该如何进行？
NSURL *url = [NSURL URLWithString:@"http://www.nyapplecountry.com/images/photosvarieties/redrome04.jpg"];
UIImage *image = [UIImage imageWithData: [NSData dataWithContentsOfURL:url]];
[self.view addSubview:[[UIImageView alloc] initWithImage:image]];
[self.containerView addSubview:self.mainView];
我在想类似的事情：
NSString *urlAddress = [NSString stringWithFormat:@"%@", place.url];
其中 place.url 来自我的数据库表。但我错过了一些东西，不确定是什么。
感谢您的帮助
Ii'm using this NSURL code to display an image. what I want to do is to insert a url from my database table in place of the static url shown in the code below:
Does anyone know how I should proceed?
NSURL *url = [NSURL URLWithString:@"http://www.nyapplecountry.com/images/photosvarieties/redrome04.jpg"];
UIImage *image = [UIImage imageWithData: [NSData dataWithContentsOfURL:url]];
[self.view addSubview:[[UIImageView alloc] initWithImage:image]];
[self.containerView addSubview:self.mainView];
I was thinking of something like:
NSString *urlAddress = [NSString stringWithFormat:@"%@", place.url];
where place.url is coming from my db table. I'm missing something though, not sure what.
thanks for any help
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place.url是一个NSString 对象以及图像的完整 URL 吗？那么事情就会很简单Is
place.urlaNSString objectand the full URL to the image? Then it would be as simple as你不能那样做。您必须从数据库读取图像并使用该数据初始化 UIImage。
You can't do it that way. You have to read image from data base and initialize UIImage with that data.