以编程方式获取 ASP.NET MVC 应用程序的控制器地址

Question

假设我想从 MVC 应用程序发送一封电子邮件，其中包含返回某个项目的链接。

所以我想在我的控制器中添加一些东西，例如：

string link = "www.mysite/mycontroller/itemdetails/23"; 

我可以以编程方式检索它，以便它可以在我发生的任何服务器/配置上工作吗？

例如

string link = GetCurrentActionRoute() + "23";

Answer 1

public ActionResult Index()
{
    string link = Url.Action(
        (string)RouteData.Values["action"],
        (string)RouteData.Values["controller"], 
        new { id = "23" }, 
        Request.Url.Scheme
    );
    // TODO: do something with the generated link
    return View();
}

Answer 2

我使用控制器类中的以下扩展方法来生成各种操作的链接。

示例：

string link = this.Action("Play");
string fullLink = this.FullUrlAction("Play", new { id = 1 });

方法：

/// <summary>
/// Helper Extensions to the Controller class.
/// </summary>
public static class ControllerExtensions
{
    /// <summary>
    /// Get an action link for a controller.
    /// </summary>
    /// <param name="controller">Controller instance.</param>
    /// <param name="action">Action to provide the link for.</param>
    /// <returns>Link Url for the Action.</returns>
    public static string Action(this Controller controller, string action) 
    {
        RouteValueDictionary rvd = new RouteValueDictionary
                                       {
                                           { "controller", controller.GetType().Name }, 
                                           { "action", action }
                                       };

        return RouteTable.Routes.GetVirtualPath(controller.ControllerContext.RequestContext, rvd).VirtualPath;
    }

    /// <summary>
    /// Get an action link for a controller.
    /// </summary>
    /// <param name="controller">Controller instance.</param>
    /// <param name="action">Action Name.</param>
    /// <param name="parameters">Action Parameters.</param>
    /// <returns>Link Url for the action with parameters.</returns>
    public static string Action(this Controller controller, string action, object parameters)
    {
        string controllerName = controller.GetType().Name;
        if (controllerName.EndsWith("Controller"))
        {
            controllerName = controllerName.Substring(0, controllerName.Length - 10);
        }

        return controller.Action(controllerName, action, parameters);
    }

    /// <summary>
    /// Get an action link for a controller.
    /// </summary>
    /// <param name="controller">Controller instance.</param>
    /// <param name="targetController">Target controller for action.</param>
    /// <param name="action">Action Name.</param>
    /// <param name="parameters">Action Parameters.</param>
    /// <returns>Link Url for the action on the given controller.</returns>
    public static string Action(this Controller controller, string targetController, string action, object parameters)
    {
        RouteValueDictionary rvd = new RouteValueDictionary(parameters)
                                       {
                                           { "controller", targetController }, 
                                           { "action", action }
                                       };

        return RouteTable.Routes.GetVirtualPath(controller.ControllerContext.RequestContext, rvd).VirtualPath;
    }

    /// <summary>
    /// Get a fully qualified action link for a controller.
    /// </summary>
    /// <param name="controller">Controller instance.</param>
    /// <param name="action">Action Name.</param>
    /// <param name="parameters">Action Parameters.</param>
    /// <param name="requestUrl">Current request URI.</param>
    /// <returns>Fully qualified Link Url.</returns>
    public static string FullUrlAction(this Controller controller, string action, object parameters, Uri requestUrl)
    {
        string controllerName = controller.GetType().Name;
        if (controllerName.EndsWith("Controller"))
        {
            controllerName = controllerName.Substring(0, controllerName.Length - 10);
        }

        return controller.FullUrlAction(controllerName, action, parameters, requestUrl);
    }

    /// <summary>
    /// Get a fully qualified action link for a controller.
    /// </summary>
    /// <param name="controller">Controller instance.</param>
    /// <param name="targetController">Target controller for action.</param>
    /// <param name="action">Action Name.</param>
    /// <param name="parameters">Action Parameters.</param>
    /// <param name="requestUrl">Current request URI.</param>
    /// <returns>Fully Qualified Link Url.</returns>
    public static string FullUrlAction(this Controller controller, string targetController, string action, object parameters, Uri requestUrl)
    {
        string testUrl = VirtualPathUtility.ToAbsolute(controller.Action(targetController, action, parameters));
        return new Uri(requestUrl, testUrl).ToString();
    }
}

Answer 3

如果链接指向与应用程序相同的位置，您可以考虑使用 Url.Action(...) 及其重载。

例如。

string actionRoute = Url.Action("action method name","controller name");

如果你想获得完整的路径，你可以使用 :

string domainRoute = HttpContext.Request.Url.AbsolutePath;

，然后将 id 与它连接起来。