如何通过 Applescript 进入/退出/越过 Xcode 调试器？
我正在开发一个 iOS 应用程序。我在模拟器上花了很多时间，如果我不必切换回 Xcode 来访问调试器单步进入/退出/结束/继续控制，那将会非常有帮助。有没有办法在 Xcode 不成为焦点应用程序的情况下做到这一点？
（我知道迷你调试器，但它没有步骤控件，而且我更喜欢键盘快捷键。）
我认为它可能是可编写脚本的，但似乎在Xcode AppleScript 字典。 （无论如何，我绝对不是 AppleScript 专家。）
我认为 GUI 脚本不会得到我想要的东西，因为它会切换到 Xcode 步骤并切换回来。但如果速度足够快，可能总比没有好。
有没有办法将键盘命令发送到没有焦点的应用程序？
还有其他想法吗？
I am developing an iOS application. I spend a lot of time in the simulator and it would be really helpful if I didn't have to switch back to Xcode to access the debuggers step in/out/over/continue controls. Is there a way to do this without Xcode being the application with focus?
(I know about the mini debugger, but that doesn't have step controls on it, and I'd prefer keyboard shortcuts.)
I thought it might be scriptable, but it didn't seem like there was a hook for it in the Xcode AppleScript dictionary. (I'm definitely not an AppleScript expert by any means, though.)
I don't think GUI scripting would get me what I want since it would switch to Xcode step and switch back. But it might be better than nothing if it was fast enough.
Is there a way to send a keyboard command to an application that's doesn't have focus?
Any other ideas?
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要查看 Xcode 的脚本支持，请启动脚本编辑器，找到“打开词典”命令，然后选择 Xcode。
To see Xcode's scripting support, launch Script Editor, find the Open Dictionary command, and select Xcode.
正如其他人提到的，使用 UI 脚本。因此，要在调试器中单步执行代码，您可以在 Applescript 中使用此代码：
在 Appscript 中使用此代码：
As others mentioned use UI scripting. So to step through code in the debugger you'd use this in Applescript:
And this in Appscript:
如果不使用 UI 脚本，您似乎无法做到这一点，我试图避免这样做。 （不过，如果您想这样做，请参阅 Clark 的回答。） Xcode 3 和 Xcode 4.3.1 似乎就是这种情况。
It doesn't seem like you can do this without using UI scripting, which I try to avoid. (See Clark's answer if you want to do that, though.) This appears to be the case for Xcode 3 and Xcode 4.3.1.