这会被视为内存泄漏吗？
考虑这个毫无意义的程序：
/* main.c */
#include <stdlib.h>
#include <unistd.h>
int main(int argc, char **argv) {
int i;
for (i = 0; i < 1024; i++) {
int pid = fork();
int status;
if (pid) {
wait(&status);
}
else {
char *ptr = (char *)malloc(1024*sizeof(char));
char *args[2] = {"Hello, world!", NULL};
execve("/bin/echo", args, NULL);
}
}
}
释放 ptr 是否不会构成 main.c 或其他程序的内存泄漏，或者在调用 execve 时它是否会被释放？
Consider this pointless program:
/* main.c */
#include <stdlib.h>
#include <unistd.h>
int main(int argc, char **argv) {
int i;
for (i = 0; i < 1024; i++) {
int pid = fork();
int status;
if (pid) {
wait(&status);
}
else {
char *ptr = (char *)malloc(1024*sizeof(char));
char *args[2] = {"Hello, world!", NULL};
execve("/bin/echo", args, NULL);
}
}
}
Would not freeing ptr constitute a memory leak for either main.c or the other program, or is it going to be freed anyway when execve is called?
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不。
这不是内存泄漏。
exec*()将在 args 数组中制作字符串数据的本地副本，然后清除子进程内存映像并将其与/bin/echo< 使用的内存映像覆盖。 /代码>。基本上 exec() 之后剩下的就是 pid。编辑：
User318904 提出了 exec() 返回 -1 （即失败）的情况。在这种情况下，已分叉但无法执行的子进程确实在技术上存在内存泄漏，但由于对失败的执行的通常响应是无论如何都退出子进程，因此操作系统将回收内存。尽管如此，释放它可能是一个好习惯，如果没有其他原因，它会让你以后不再想知道它。
No.
This is not a memory leak.
exec*()will make a local copy of the string data in the args array, then blow away the child process memory image and overlay it with the memory image used by/bin/echo. Essentially all that remains after the exec() is the pid.Edit:
User318904 brought up the case of exec() returning -1 (i.e., failure). In this case, the child process that has forked but failed to exec does, indeed technically have a memory leak, but as the usual response to a failed exec is to just exit the child process anyways, the memory will be reclaimed by the OS. Still, freeing it is probably a good habit to get into, if for no other reason than that it will keep you from wondering about it later on.
当execve返回-1时，是的。否则，也许吧。
When execve returns -1, yes. Otherwise, maybe.
分配的内存应该由
exec释放。通话结束后您无论如何都无法访问它。The allocated memory should be freed by
exec. After the call completes you can't access it anyway.