执行 GROUP BY 时强制将特定记录置顶
我有以下 MySQL 查询和从中查询的表:
SELECT
`Song`.`id`,
`Song`.`file_name`,
`User`.`first_name`,
`Vote`.`value`,
Sum(`Vote`.`value`) AS score
FROM `songs` AS `Song`
LEFT JOIN votes AS `Vote` ON (`Song`.`id`=`Vote`.`song_id`)
LEFT JOIN `users` AS `User` ON (`Song`.`user_id` = `User`.`id`)
GROUP BY `Vote`.`song_id`
LIMIT 20;
mysql> describe songs;
+-----------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| file_name | varchar(255) | NO | | NULL | |
| user_id | int(11) | NO | | NULL | |
| created | datetime | NO | | NULL | |
| modified | datetime | NO | | NULL | |
+-----------+--------------+------+-----+---------+----------------+
5 rows in set (0.00 sec)
mysql> describe users;
+------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| username | varchar(255) | NO | | NULL | |
| password | varchar(255) | NO | | NULL | |
| first_name | varchar(255) | NO | | NULL | |
| last_name | varchar(255) | NO | | NULL | |
| is_admin | tinyint(1) | NO | | 0 | |
| created | datetime | NO | | NULL | |
| modified | datetime | NO | | NULL | |
+------------+--------------+------+-----+---------+----------------+
mysql> describe votes;
+----------+----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------+----------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| value | int(11) | NO | | NULL | |
| song_id | int(11) | NO | | NULL | |
| user_id | int(11) | NO | | NULL | |
| created | datetime | NO | | NULL | |
| modified | datetime | NO | | NULL | |
+----------+----------+------+-----+---------+----------------+
该查询功能就像我想要的那样,除了一件事之外。 Vote.value 字段中返回的值不是来自与登录应用程序的用户关联的行。我需要得分值是所有值的总和,无论它与哪个用户关联,但 Vote.value 字段应该属于登录用户(每个用户每首歌只能获得一个投票记录)。
我的第一个想法是以某种方式对表进行排序,以便当分组发生时,登录用户的投票记录位于顶部,但我不知道如何进行强制任意值到顶部的排序。任何想法都会非常有帮助。
I have the following MySQL query and tables from which I am querying:
SELECT
`Song`.`id`,
`Song`.`file_name`,
`User`.`first_name`,
`Vote`.`value`,
Sum(`Vote`.`value`) AS score
FROM `songs` AS `Song`
LEFT JOIN votes AS `Vote` ON (`Song`.`id`=`Vote`.`song_id`)
LEFT JOIN `users` AS `User` ON (`Song`.`user_id` = `User`.`id`)
GROUP BY `Vote`.`song_id`
LIMIT 20;
mysql> describe songs;
+-----------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| file_name | varchar(255) | NO | | NULL | |
| user_id | int(11) | NO | | NULL | |
| created | datetime | NO | | NULL | |
| modified | datetime | NO | | NULL | |
+-----------+--------------+------+-----+---------+----------------+
5 rows in set (0.00 sec)
mysql> describe users;
+------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| username | varchar(255) | NO | | NULL | |
| password | varchar(255) | NO | | NULL | |
| first_name | varchar(255) | NO | | NULL | |
| last_name | varchar(255) | NO | | NULL | |
| is_admin | tinyint(1) | NO | | 0 | |
| created | datetime | NO | | NULL | |
| modified | datetime | NO | | NULL | |
+------------+--------------+------+-----+---------+----------------+
mysql> describe votes;
+----------+----------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------+----------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| value | int(11) | NO | | NULL | |
| song_id | int(11) | NO | | NULL | |
| user_id | int(11) | NO | | NULL | |
| created | datetime | NO | | NULL | |
| modified | datetime | NO | | NULL | |
+----------+----------+------+-----+---------+----------------+
This query functions just like I want except for one thing. The value returned in the field Vote.value is not from a row that is associated with the user who is logged into the application. I need the score value to be a sum of all the values no matter which user it is associated with, but the Vote.value field should belong to the logged in user (each user only gets one vote record per song).
My first thought is to somehow sort the table so that when the group by happens the vote record for the logged in user is at the top but I have no idea how to do a sort that forces an arbitrary value to the top. Any ideas would be very helpful.
如果你对这篇内容有疑问,欢迎到本站社区发帖提问 参与讨论,获取更多帮助,或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱,如果其他用户或者作者回复了您的评论,将不能在第一时间通知您!
发布评论
评论(1)
第三个连接
并将
Vote.value
替换为VotePerUser.Value
and a third join
and replace the
Vote.value
withVotePerUser.Value