php，url重写，如果url没有“？”，如何从GET中获取字符串？
我想建立一个 php 网站，并且想删除所有使 url 看起来动态的字符串。 但是我仍然需要通过 GET 获取信息，所以基本上我不知道该怎么做，因为我需要将参数传递给 $_GET 请求，这显然是动态的。例如，我可能有 www.domain.com/mobile_phones，其中 mobile_phones 将是我应该获取的参数/信息。 任何帮助将不胜感激
I would like to build a php website and I would like to remove all the strings that make the url to seem dynamic.
However I still need to get information through GET so basically I don't know how to do that because I need to pass a parameter to $_GET request which obviously would be dynamic . For example I may have www.domain.com/mobile_phones where mobile_phones would be the parameter/information that I should get .
Any help would be highly appreciated
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您可以通过称为“路由”的过程来完成此操作。通常，您设置重写规则以将所有内容转发到单个入口点 -
index.php然后index.php初始化您的应用程序，使用某种路由类。该路由类将REQUEST_URI与已知模式列表进行比较。当它匹配 i 模式时，它会解析出URI中的所有变量。另一方面，为了在应用程序中生成正确的 URL，通常有许多帮助程序，它们采用一系列参数以及控制器/操作，并根据相同的路由规则生成 URL。
查看 Zend 框架中的
Zend_Controller包作为一个很好的示例。You do this through a process called "routing". Normally you set up rewrite rule to forward everything to a single entry point -
index.phpthenindex.phpintializes youre application witch makes use of some kind of routing class. This routing class compares theREQUEST_URIto a list of known patterns. When it matches i pattern it takes car of parsing out all the variables form theURI.On the other end of things, to generate the proper urls wihtin the app there are usually a number of helpers that take a series of parameters along with a controller/action and generate a URL based on the same routing rules.
Take a look at the
Zend_Controllerpackage from Zend framework for a good example.URL 重写的工作原理是将接收到的 URL 字符串转换为更合适的格式，包括获取参数。例如，
这会将
example.com/1234/my-page字符串转换为 example.com/index.php?id=1234并且 id 将是可以直接从$_GET数组访问。URL rewriting works by translating the received URL string into a more suitable format, including get parameters. For example
This will translate a string that's says, say
example.com/1234/my-pageto example.com/index.php?id=1234and id will be accessible directly from the$_GETarray.