如何将 javax.xml.transform.Source 转换为 InputStream？

发布于 2024-09-19 11:04:07 字数 234 浏览 4 评论 0原文

如何将 javax.xml.transform.Source 转换为 InputStream？ Source 的实现是javax.xml.transform.dom.DOMSource。

Source inputSource = messageContext.getRequest().getPayloadSource();

原文

How can I convert a javax.xml.transform.Source into a InputStream? The Implementation of Source is javax.xml.transform.dom.DOMSource.

Source inputSource = messageContext.getRequest().getPayloadSource();

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幽梦紫曦～ 2024-09-26 11:04:08

首先尝试向下转换为 javax.xml.transform.stream.StreamSource。如果成功，您就可以通过 getter 访问底层的 InputStream 或 Reader。这将是最简单的方法。

如果向下转换失败，您可以尝试使用 javax.xml.transform.Transformer 将其转换为已使用java.io.ByteArrayOutputStream。然后返回一个java.io.ByteArrayInputStream。类似于：

Transformer t = // getTransformer();
ByteArrayOutputStream os = new ByteArrayOutputStream();
Result result = new StreamResult(os);
t.transform(inputSource, result);
return new ByteArrayInputStream(os.getByteArray());

当然，如果StreamSource可以是一个大文档，那么这是不可取的。在这种情况下，您可以使用临时文件和 java.io.FileOutputStream/java.io.FileInputStram。另一种选择是生成一个转换器线程并通过 java.io.PipedOutputStream/java.io.PipedInputStream 进行通信，但这更复杂：

PipedInputStream is = new PipedInputStream();
PipedOutputStream os = new PipedOutputStream(is);
Result result = new StreamResult(os);
// This creates and starts a thread that creates a transformer
// and applies it to the method parameters.
spawnTransformerThread(inputSource, result);
return is;

First try to downcast to javax.xml.transform.stream.StreamSource. If that succeeds you have access to the underlying InputStream or Reader through getters. This would be the easiest way.

If downcasting fails, you can try using a javax.xml.transform.Transformer to transform it into a javax.xml.transform.stream.StreamResult that has been setup with a java.io.ByteArrayOutputStream. Then you return a java.io.ByteArrayInputStream. Something like:

Transformer t = // getTransformer();
ByteArrayOutputStream os = new ByteArrayOutputStream();
Result result = new StreamResult(os);
t.transform(inputSource, result);
return new ByteArrayInputStream(os.getByteArray());

Of course, if the StreamSource can be a large document, this is not advisable. In that case, you could use a temporary file and java.io.FileOutputStream/java.io.FileInputStram. Another option would be to spawn a transformer thread and communicate through java.io.PipedOutputStream/java.io.PipedInputStream, but this is more complex:

PipedInputStream is = new PipedInputStream();
PipedOutputStream os = new PipedOutputStream(is);
Result result = new StreamResult(os);
// This creates and starts a thread that creates a transformer
// and applies it to the method parameters.
spawnTransformerThread(inputSource, result);
return is;

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