为什么我的 std::string 被切断？

Question

我按如下方式初始化一个字符串：

std::string myString = "'The quick brown fox jumps over the lazy dog' is an English-language pangram (a phrase that contains all of the letters of the alphabet)";

myString 最终被这样切断：

'敏捷的棕色狐狸跳过了 “懒狗”是英语 pangram（包含的短语

pangram（包含Where can i set the size limit? ） 我尝试了以下方法但没有成功：

std::string myString;
myString.resize(300);
myString = "'The quick brown fox jumps over the lazy dog' is an English-language pangram (a phrase that contains all of the letters of the alphabet)";

非常感谢！

Answer 1

当然，这只是调试器将其切断（xcode）。我刚刚开始使用 xcode/c++，所以非常感谢您的快速回复。

Answer 2

你确定吗？

kkekan> ./a.out 
'The quick brown fox jumps over the lazy dog' is an English-language pangram (a phrase that contains all of the letters of the alphabet)

没有充分的理由为什么会发生这种情况！

Answer 3

尝试以下操作（在调试模式下）：（

assert(!"Congratulations, I am in debug mode! Let's do a test now...")
std::string myString = "'The quick brown fox jumps over the lazy dog' is an English-language pangram (a phrase that contains all of the letters of the alphabet)";
assert(myString.size() > 120);

第二个）断言是否失败？

Answer 4

打印或显示文本时，输出机器会缓冲输出。 告诉它刷新缓冲区（显示所有剩余文本）：

#include <iostream>
using std::cout;
using std::endl;

int main(void)
{
  std::string myString =
    "'The quick brown fox jumps over the lazy dog'" // Compiler concatenates
    " is an English-language pangram (a phrase"     // these contiguous text
    " that contains all of the letters of the"      // literals automatically.
    " alphabet)";
  // Method 1:  use '\n'
  // A newline forces the buffers to flush.
  cout << myString << '\n';

  // Method 2:  use std::endl;
  // The std::endl flushes the buffer then sends '\n' to the output.
  cout << myString << endl;

  // Method 3:  use flush() method
  cout << myString;
  cout.flush();

  return 0;
}

您可以通过输出 '\n' 或使用 std::endl 或执行 flush() 方法来 有关缓冲区的更多信息，请在 Stack Overflow 中搜索“C++ 输出缓冲区”。