Android 小部件在 Remoteviews 更新时从模拟器中消失

发布于 2024-09-19 01:35:24 字数 1955 浏览 4 评论 0原文

我的 MySQL DB 表包含一个以 image_id 作为键的 BLOB 图像。我正在尝试执行以下操作。

1.来自 Android 应用程序的 HttpPost("http://example.com/RetrieveImage.php")名称值对中的 image_id。

PHP 脚本如下：

<?php
mysql_connect("host","userid","password");
mysql_select_db("database");
$q=mysql_query("SELECT image FROM testblob WHERE image_id =".$_REQUEST['image_id']."");
$e=mysql_fetch_assoc($q);
print($e);
mysql_close();
?>

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
输入流=entity.getContent(); 
响应 = httpclient.execute(httppost);
HttpEntity实体=response.getEntity();
is =entity.getContent();

将Inputstream对象中的BLOB数据存储为字节数组

ByteArrayOutputStream baos = new ByteArrayOutputStream();
        字节[] buf = 新字节[10240];
        整数 n = 0;
        尝试 {
            while ((n=is.read(buf))>=0)
            {
            baos.write(buf, 0, n);
            }
is.close();
byte[] bytes = baos.toByteArray();

将字节数组转换为位图并将Android widget的ImageView设置为Image< /p>

Bitmap 位图；
远程视图 updateViews = null;
bitmap = BitmapFactory.decodeByteArray(bytes, 0, bytes.length);
updateViews = new RemoteViews(context.getPackageName(), R.layout.tuwidget);
updateViews.setImageViewBitmap(R.id.tuwidget_img_btn, 位图);
return updateViews;

一旦运行，我不知道为什么该小部件甚至没有显示在模拟器上甚至无法再将小部件添加到屏幕上。我做错了什么？非常感谢任何帮助。

哦，这是我的小部件布局。

<?xml version="1.0" encoding="utf-8"?>
<AbsoluteLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/tuwidget"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
>
<ImageView
android:id="@+id/tuwidget_img_btn"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
>
</ImageView>
</AbsoluteLayout>

原文

My MySQL DB table holds a BLOB image with image_id as key. I am trying to do the following.

1.HttpPost("http://example.com/RetrieveImage.php") from Android App with the image_id in name value pairs.

The PHP Script is as follows:

<?php
mysql_connect("host","userid","password");
mysql_select_db("database");
$q=mysql_query("SELECT image FROM testblob WHERE image_id =".$_REQUEST['image_id']."");
$e=mysql_fetch_assoc($q);
print($e);
mysql_close();
?>

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
InputStream is = entity.getContent(); 
response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();

Store the BLOB data in Inputstream object is to byte array

ByteArrayOutputStream baos = new ByteArrayOutputStream();
        byte[] buf = new byte[10240];
        int n = 0;
        try {
            while ((n=is.read(buf))>=0)
            {
            baos.write(buf, 0, n);
            }
is.close();
byte[] bytes = baos.toByteArray();

Convert the byte array to bitmap and set ImageView of the Android widget to the Image

Bitmap bitmap;
RemoteViews updateViews = null;
bitmap = BitmapFactory.decodeByteArray(bytes, 0, bytes.length);
updateViews = new RemoteViews(context.getPackageName(), R.layout.tuwidget);
updateViews.setImageViewBitmap(R.id.tuwidget_img_btn, bitmap);
return updateViews;

Once this is run, I dont know why the widget does not even show up on the emulator and
cannot even add the widget anymore to the screen. What am I doing wrong? Any help is much appreciated.

Oh and here is my widget layout.

<?xml version="1.0" encoding="utf-8"?>
<AbsoluteLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/tuwidget"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
>
<ImageView
android:id="@+id/tuwidget_img_btn"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
>
</ImageView>
</AbsoluteLayout>

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Oo萌小芽oO 2024-09-26 01:35:24

遇到问题 - 位图返回 Null，因此小部件初始布局消失了。问题出在 php.ini 中。

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丑丑阿 2024-09-26 01:35:24

现在可以了！！！在浏览器和应用程序上

新的 php：

<?php
mysql_connect("host","login","password");
mysql_select_db("dbname");
$q=mysql_query("SELECT picture FROM tablename WHERE id>='".$_REQUEST['id']."'");

$e=mysql_fetch_row($q);
header('Content-Length: '.strlen($e[0]));
header('Content-type: image/jpg');
echo $e[0];
mysql_close();?>

Now it works!!! on browser and app

new php:

<?php
mysql_connect("host","login","password");
mysql_select_db("dbname");
$q=mysql_query("SELECT picture FROM tablename WHERE id>='".$_REQUEST['id']."'");

$e=mysql_fetch_row($q);
header('Content-Length: '.strlen($e[0]));
header('Content-type: image/jpg');
echo $e[0];
mysql_close();?>

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