如何检索目录中的所有文件名？

发布于 2024-09-18 23:39:16 字数 159 浏览 2 评论 0原文

如何检索目录中与某个模式匹配的所有文件名？我尝试了这个，但它返回完整路径而不是文件名。

Directory.GetFiles (path, "*.txt")

我是否必须手动从结果中裁剪目录路径？这很简单，但也许有一个更简单的解决方案:)

原文

How do I retrieve all filenames matching a pattern in a directory? I tried this but it returns the full path instead of the filename.

Directory.GetFiles (path, "*.txt")

Do I have to manually crop the directory path off of the result? It's easy but maybe there is an even simpler solution :)

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烟沫凡尘 2024-09-25 23:39:16

foreach (string s in Directory.GetFiles(path, "*.txt").Select(Path.GetFileName))
       Console.WriteLine(s);

foreach (string s in Directory.GetFiles(path, "*.txt").Select(Path.GetFileName))
       Console.WriteLine(s);

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郁金香雨 2024-09-25 23:39:16

假设您使用 C#，DirectoryInfo 类将对您更有用：

DirectoryInfo directory = new DirectoryInfo(path);
FileInfo[] files = directory.GetFiles("*.txt");

FileInfo 类包含一个属性 Name，它返回不带路径的名称。

请参阅DirectoryInfo 文档和FileInfo 文档了解更多信息。

Assuming you're using C#, the DirectoryInfo class will be of more use to you:

DirectoryInfo directory = new DirectoryInfo(path);
FileInfo[] files = directory.GetFiles("*.txt");

The FileInfo class contains a property Name which returns the name without the path.

See the DirectoryInfo documentation and the FileInfo documentation for more information.

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硬不硬你别怂 2024-09-25 23:39:16

您想通过子目录递归吗？使用 Directory.EnumerateFiles：

var fileNames = Directory.EnumerateFiles(@"\", "*.*", SearchOption.AllDirectories);

Do you want to recurse through subdirectories? Use Directory.EnumerateFiles:

var fileNames = Directory.EnumerateFiles(@"\", "*.*", SearchOption.AllDirectories);

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瞎闹 2024-09-25 23:39:16

在代码中使用 Path.GetFileName ：

foreach(var file in Directory.GetFiles(path, "*.txt"))
{
   Console.WriteLine(Path.GetFileName(file));
}

另一个解决方案：

DirectoryInfo dir = new DirectoryInfo(path);
var files = dir.GetFiles("*.txt");
foreach(var file in files)
{
   Console.WriteLine(file.Name);
}

Use Path.GetFileName with your code:

foreach(var file in Directory.GetFiles(path, "*.txt"))
{
   Console.WriteLine(Path.GetFileName(file));
}

Another solution:

DirectoryInfo dir = new DirectoryInfo(path);
var files = dir.GetFiles("*.txt");
foreach(var file in files)
{
   Console.WriteLine(file.Name);
}

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信仰 2024-09-25 23:39:16

您可以使用以下代码来获取文件名：

    DirectoryInfo info  = new DirectoryInfo("C:\Test");
    FileInfo[] files = info.GetFiles("*.txt");

    foreach(FileInfo file in files)
    {
        string fileName = file.Name;
    }

You can use the following code to obtain the filenames:

    DirectoryInfo info  = new DirectoryInfo("C:\Test");
    FileInfo[] files = info.GetFiles("*.txt");

    foreach(FileInfo file in files)
    {
        string fileName = file.Name;
    }

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鯉魚旗 2024-09-25 23:39:16

var filenames = Directory.GetFiles(@"C:\\Images", "*.jpg").
                Select(filename => Path.GetFileNameWithoutExtension(filename)).
                ToArray();

如果这是你想要的，试试这个

var filenames = Directory.GetFiles(@"C:\\Images", "*.jpg").
                Select(filename => Path.GetFileNameWithoutExtension(filename)).
                ToArray();

Try this if it is what you want

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神经暖 2024-09-25 23:39:16

试试这个

IEnumerable<string> fileNames =
                Directory.GetFiles(@"\\srvktfs1\Metin Atalay\", "*.dll")
                    .Select(Path.GetFileNameWithoutExtension);

Try this

IEnumerable<string> fileNames =
                Directory.GetFiles(@"\\srvktfs1\Metin Atalay\", "*.dll")
                    .Select(Path.GetFileNameWithoutExtension);

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~没有更多了~