Django 和 xlrd,从内存中读取

发布于 2024-09-18 08:37:50 字数 1438 浏览 9 评论 0原文

我的计划是让用户上传一个excel文件,上传后我将显示可编辑的表单,其中包含上传的excel的内容,一旦用户确认输入正确,他/她点击保存按钮,这些项目就会被保存在某些模型上。

为此,我编写了以下视图和表单:

form:

IMPORT_FILE_TYPES = ['.xls', ]

class XlsInputForm(forms.Form):
    input_excel = forms.FileField(required= True, label= u"Upload the Excel file to import to the system.")

    def clean_input_excel(self):
        input_excel = self.cleaned_data['input_excel']
        extension = os.path.splitext( input_excel.name )[1]
        if not (extension in IMPORT_FILE_TYPES):
            raise forms.ValidationError( u'%s is not a valid excel file. Please make sure your input file is an excel file (Excel 2007 is NOT supported.' % extension )
        else:
            return input_excel

view:

def import_excel_view(request):
    if request.method == 'POST':
        form = XlsInputForm(request.POST, request.FILES)
        if form.is_valid():
            input_excel = request.FILES['input_excel']
            # I need to open this input_excel with input_excel.open_workbook()
            return render_to_response('import_excel.html', {'rows': rows})
    else:
        form = XlsInputForm()

    return render_to_response('import_excel.html', {'form': form})

正如您在 # 中看到的,我需要使用 input_excel.open_workbook( 打开此 input_excel ) 我需要从内存中读取,但是 open_workbook 从文件中读取,而不将此输入保存到某个地方,我该如何读取它?

My plan is to let a user to upload an excel file, once uploaded I will be displaying editable form which contains the content of the uploaded excel, once user confirms the input is correct, he/she hits the save button and these items are saved at some model.

For this, I have written this view and form:

form:

IMPORT_FILE_TYPES = ['.xls', ]

class XlsInputForm(forms.Form):
    input_excel = forms.FileField(required= True, label= u"Upload the Excel file to import to the system.")

    def clean_input_excel(self):
        input_excel = self.cleaned_data['input_excel']
        extension = os.path.splitext( input_excel.name )[1]
        if not (extension in IMPORT_FILE_TYPES):
            raise forms.ValidationError( u'%s is not a valid excel file. Please make sure your input file is an excel file (Excel 2007 is NOT supported.' % extension )
        else:
            return input_excel

view:

def import_excel_view(request):
    if request.method == 'POST':
        form = XlsInputForm(request.POST, request.FILES)
        if form.is_valid():
            input_excel = request.FILES['input_excel']
            # I need to open this input_excel with input_excel.open_workbook()
            return render_to_response('import_excel.html', {'rows': rows})
    else:
        form = XlsInputForm()

    return render_to_response('import_excel.html', {'form': form})

As you can see at the # I need to open this input_excel with input_excel.open_workbook() I need to read from memory but open_workbook reads from a file, without saving this input to somewhere, how can I read it ?

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如梦初醒的夏天 2024-09-25 08:37:50
if form.is_valid():
    input_excel = request.FILES['input_excel']
    book = xlrd.open_workbook(file_contents=input_excel.read())

    # your work with workbook 'book'

    return render_to_response('import_excel.html', {'rows': rows})

当提供file_contents可选关键字时,filename关键字将不会被使用。

快乐编码。

if form.is_valid():
    input_excel = request.FILES['input_excel']
    book = xlrd.open_workbook(file_contents=input_excel.read())

    # your work with workbook 'book'

    return render_to_response('import_excel.html', {'rows': rows})

When file_contents optional keyword is provided, filename keyword will not be used.

Happy Coding.

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