Propel 选择条件中的 IF 语句

发布于 2024-09-18 07:42:55 字数 1603 浏览 7 评论 0原文

我正在尝试将 IF 语句纳入我的推进标准中。 这就是我建立标准的方式:

$c = is_object($c) ? $c : new Criteria();
$c->addSelectColumn("CONCAT(DAYOFYEAR(" . SomePeer::CREATED_AT . "), ' ', YEAR(" . SomePeer::CREATED_AT . ")) AS period");
$c->addSelectColumn("COUNT(" . SomePeer::ID . ") AS registrations");
$c->addSelectColumn("COUNT(IF(" . SomePeer::JOIN . " > 0 AND " . SomePeer::JOIN . " < 3, 1, NULL)) AS coreg");
$c->addJoin(SomePeer::IDENTIFIER, self::TRACKING_IDENTIFIER);
$c->add(SomePeer::ASSOCIATE_ID, $user->getId());
$c->addJoin(self::USER_ID, SomePeer::ID);
$c->addJoin(SomePeer::ID, SomePeer::USER_ID);
$c->add(SomePeer::CREDENTIAL, 'student');
$c->addJoin(SomePeer::PROFILE_ID, SomePeer::ID);

但是,当检查生成的 SQL 时,我得到以下信息:

SELECT CONCAT(MONTHNAME(some_table.CREATED_AT), ' ', YEAR(some_table.CREATED_AT)) AS period, COUNT(some_table.ID) AS registrations, COUNT(IF(some_table.JOIN > 0 AND some_table.JOIN < 3, 1, NULL)) AS coreg 
FROM `some_table`, `>` `0` `AND` `some_table`, `some_table`, `some_table`, `some_table`, `some_table` 
WHERE some_table.ASSOCIATE_ID=:p1 
AND some_table.CREDENTIAL=:p2 
AND some_table.IDENTIFIER=some_table.TRACKING_IDENTIFIER 
AND some_table.STUDENT_USER_ID=some_table.ID 
AND some_table.ID=some_table.USER_ID 
AND some_table.PROFILE_ID=some_table.ID 
# Params: some_table.ASSOCIATE_ID => 6, some_table.CREDENTIAL => 'credential'"

基本上,如您所见,查询的 FROM 部分都是错误的。我猜 propel 将 COUNT 中的 IF 语句的一部分误认为是表名,并将它们包含在查询的 FROM 部分中。 有谁知道我如何解决这个问题,或者有人甚至能够让一些东西发挥作用?

感谢您的帮助,

文森特

I am trying to incorporate an IF statement into my propel criteria.
This is the how I build up my criteria:

$c = is_object($c) ? $c : new Criteria();
$c->addSelectColumn("CONCAT(DAYOFYEAR(" . SomePeer::CREATED_AT . "), ' ', YEAR(" . SomePeer::CREATED_AT . ")) AS period");
$c->addSelectColumn("COUNT(" . SomePeer::ID . ") AS registrations");
$c->addSelectColumn("COUNT(IF(" . SomePeer::JOIN . " > 0 AND " . SomePeer::JOIN . " < 3, 1, NULL)) AS coreg");
$c->addJoin(SomePeer::IDENTIFIER, self::TRACKING_IDENTIFIER);
$c->add(SomePeer::ASSOCIATE_ID, $user->getId());
$c->addJoin(self::USER_ID, SomePeer::ID);
$c->addJoin(SomePeer::ID, SomePeer::USER_ID);
$c->add(SomePeer::CREDENTIAL, 'student');
$c->addJoin(SomePeer::PROFILE_ID, SomePeer::ID);

However when inspecting the resulting SQL I get the following:

SELECT CONCAT(MONTHNAME(some_table.CREATED_AT), ' ', YEAR(some_table.CREATED_AT)) AS period, COUNT(some_table.ID) AS registrations, COUNT(IF(some_table.JOIN > 0 AND some_table.JOIN < 3, 1, NULL)) AS coreg 
FROM `some_table`, `>` `0` `AND` `some_table`, `some_table`, `some_table`, `some_table`, `some_table` 
WHERE some_table.ASSOCIATE_ID=:p1 
AND some_table.CREDENTIAL=:p2 
AND some_table.IDENTIFIER=some_table.TRACKING_IDENTIFIER 
AND some_table.STUDENT_USER_ID=some_table.ID 
AND some_table.ID=some_table.USER_ID 
AND some_table.PROFILE_ID=some_table.ID 
# Params: some_table.ASSOCIATE_ID => 6, some_table.CREDENTIAL => 'credential'"

Basically, as you can see, the FROM part of the query is all wrong. I guess propel mistook part of the IF statement in the COUNT as table names and included them in the FROM part of the query.
Has anyone got any ideas how I could get 'round this problem or has someone even been able to get something to work?

Thanks for all your help,

Vincent

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动听の歌 2024-09-25 07:42:55

问题似乎出在 JOIN 名称上。您是否使用“join”作为字段名称???在那里尝试一个不同的名称。

Seems like the problem is with the name JOIN. Are you using "join" as a field name??? Try a different name there.

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