Google 代码值错误上的 Mercurial 推送错误

Question

我正在尝试通过推送 Google 代码来学习使用 Mercurial。

我有两个 .hgrc 文件：一个文件位于 $PROJECT_DIR/.hg/.hrgc 和 $HOME/.hgrc。我有两个单独的文件，因为我不想将密码放在中央存储库上。

这是 $PROJECT_DIR/.hg/.hrgc 的内容：

[ui]
usermane=Venkat S. Rao <[email protected]>
verbose=true

[paths]
default-push =https:vrao423:gc4yy3vB3mc4@//personal-site423.googlecode.com/hg/us

这是 $HOME/.hgrc 的内容：

[ui]
username= Venkat Rao <[email protected]>
verbose=True

[auth]
project.prefix=https://personal-site423.googlecode.com/hg/
password=###
username=vrao423

---

对于用户名，我有我的 Gmail ID。

我可以将更改提交到本地存储库，但是当我尝试 hg Push 时，出现此错误。

** unknown exception encountered, details follow
** report bug details to http://mercurial.selenic.com/bts/
** or [email protected]
** Mercurial Distributed SCM (version 1.4.3)
** Extensions loaded: 
Traceback (most recent call last):
  File "/usr/bin/hg", line 27, in 
    mercurial.dispatch.run()
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 16, in run
    sys.exit(dispatch(sys.argv[1:]))
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 30, in dispatch
    return _runcatch(u, args)
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 46, in _runcatch
    return _dispatch(ui, args)
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 454, in _dispatch
    return runcommand(lui, repo, cmd, fullargs, ui, options, d)
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 324, in runcommand
    ret = _runcommand(ui, options, cmd, d)
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 505, in _runcommand
    return checkargs()
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 459, in checkargs
    return cmdfunc()
  File "/usr/lib/pymodules/python2.6/mercurial/dispatch.py", line 453, in 
    d = lambda: util.checksignature(func)(ui, *args, **cmdoptions)
  File "/usr/lib/pymodules/python2.6/mercurial/util.py", line 386, in check
    return func(*args, **kwargs)
  File "/usr/lib/pymodules/python2.6/mercurial/commands.py", line 2345, in push
    other = hg.repository(cmdutil.remoteui(repo, opts), dest)
  File "/usr/lib/pymodules/python2.6/mercurial/hg.py", line 63, in repository
    repo = _lookup(path).instance(ui, path, create)
  File "/usr/lib/pymodules/python2.6/mercurial/httprepo.py", line 263, in instance
    inst.between([(nullid, nullid)])
  File "/usr/lib/pymodules/python2.6/mercurial/httprepo.py", line 184, in between
    d = self.do_read("between", pairs=n)
  File "/usr/lib/pymodules/python2.6/mercurial/httprepo.py", line 128, in do_read
    fp = self.do_cmd(cmd, **args)
  File "/usr/lib/pymodules/python2.6/mercurial/httprepo.py", line 80, in do_cmd
    resp = self.urlopener.open(urllib2.Request(cu, data, headers))
  File "/usr/lib/python2.6/urllib2.py", line 391, in open
    response = self._open(req, data)
  File "/usr/lib/python2.6/urllib2.py", line 409, in _open
    '_open', req)
  File "/usr/lib/python2.6/urllib2.py", line 369, in _call_chain
    result = func(*args)
  File "/usr/lib/pymodules/python2.6/mercurial/url.py", line 455, in https_open
    self.auth = self.pwmgr.readauthtoken(req.get_full_url())
  File "/usr/lib/pymodules/python2.6/mercurial/url.py", line 141, in readauthtoken
    group, setting = key.split('.', 1)
ValueError: need more than 1 value to unpack

请帮我。我尝试阅读 hgrc man，但这只是胡言乱语。

谢谢 文卡特

Answer 1

我是一名 Mercurial 开发人员。请在 邮件列表 或在我们的 错误跟踪器。我很想听听您的意见，以便我们可以使手册页变得更好，所以请写信给我们，告诉我们您发现哪一部分是“乱码”。

在这种特殊情况下，问题是您需要编写 auth 部分 像这样：

[auth]
project.prefix=https://personal-site423.googlecode.com/hg/
project.password=###
project.username=vrao423

我将用 googlecode 或类似的东西替换 project 。我们当然应该报告一些合理的内容而不是回溯，我可以看到我们已经修复了这个特定的错误Mercurial 1.5 中的。