java：等待另一个线程执行一条语句n次

发布于 2024-09-17 11:39:41 字数 333 浏览 5 评论 0原文

停止线程并等待另一个线程执行语句（或方法）一定次数的最佳方法是什么？我正在考虑这样的事情（让“number”是一个 int）：

number = 5;
while (number > 0) {
   synchronized(number) { number.wait(); }
}

...

synchronized(number) {
   number--;
   number.notify();
}

显然这是行不通的，首先因为你似乎不能在 int 类型上 wait() 。此外，对于这样一个简单的任务，我想到的所有其他解决方案都非常复杂。有什么建议吗？（谢谢！）

原文

what is the best way to stop a thread and wait for a statement (or a method) to be executed a certain number of times by another thread?
I was thinking about something like this (let "number" be an int):

number = 5;
while (number > 0) {
   synchronized(number) { number.wait(); }
}

...

synchronized(number) {
   number--;
   number.notify();
}

Obviously this wouldn't work, first of all because it seems you can't wait() on a int type. Furthermore, all other solutions that come to my java-naive mind are really complicated for such a simple task. Any suggestions? (Thanks!)

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蓝海 2024-09-24 11:39:41

听起来您正在寻找 CountDownLatch。

CountDownLatch latch = new CountDownLatch(5);
...
latch.await(); // Possibly put timeout


// Other thread... in a loop
latch.countDown(); // When this has executed 5 times, first thread will unblock

信号量< /a> 也可以工作：

Semaphore semaphore = new Semaphore(0);
...
semaphore.acquire(5);

// Other thread... in a loop
semaphore.release(); // When this has executed 5 times, first thread will unblock

Sounds like you're looking for CountDownLatch.

CountDownLatch latch = new CountDownLatch(5);
...
latch.await(); // Possibly put timeout


// Other thread... in a loop
latch.countDown(); // When this has executed 5 times, first thread will unblock

A Semaphore would also work:

Semaphore semaphore = new Semaphore(0);
...
semaphore.acquire(5);

// Other thread... in a loop
semaphore.release(); // When this has executed 5 times, first thread will unblock

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